The factors of 60 are:
1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, 60
The factors of 68 are:
1, 2, 4, 17, 34, 68
They are evenly divisible by 4.
The greatest common factor of 12, 60, and 68 is 4.
60
No, 60 is.
a number is 6. All numbers divisible by both 4 and 15 are the multiples of 4 and 15. Since 4 and 15 have no prime factor in common (4 = 22, 15 = 3 · 5), then the least common multiple of 4 and 15 is equal to their product, namely 4 · 15 = 60. Every other multiple of 4 and 15 is divisible by 60. Thus, if 60 is divisible by a number then all the multiples of 4 and 15 are divisible by that number. Therefore, it is enough to check by which number in the given options is 60 divisible. Only 6 divides 60 and none of the other do. The answer must be (A).
The GCF is 4.
68 is divisible by 17 but not by 3.
Well, like any other real number, 68 is divisible by any number except for 0, as division by zero is undefined. 68 is evenly divisible (with no remainder) by: 1; 2; 4; 17; 34; 68 [hope I did not miss any]
no
2,4,1,68
No. 68 is not evenly divisible by 15.
No because 68/13 is 5.23076923
68. 68 is divisible by 17.
3,468
42, 48, 54, and 60 is. -- If it's 'even' then it must also be divisible by 2 . -- If it's divisible by 3 and also by 2, then it must be divisible by 6 . -- The multiples of 6 between 40 and 60 are 42, 48, 54, and 60 .
The answer is (60/68)*100% = 88.235%.
60/4 = 15 Therefore, 60 is divisible by 4.
A number is divisible by 3 if the sum of its digits is divisible by 3. The sum of the digits of 60 is 6 + 0 = 6, which is divisible by 3, so, yes, 60 is divisible by 3. 60 ÷ 3 = 20