60
To find the greatest common factor (GCF) of 12, 60, and 68, we first need to find the prime factorization of each number. The prime factorization of 12 is 2^2 * 3, the prime factorization of 60 is 2^2 * 3 * 5, and the prime factorization of 68 is 2^2 * 17. The GCF is the product of the common prime factors raised to the lowest power, which in this case is 2^2 = 4. Therefore, the greatest common factor of 12, 60, and 68 is 4.
52, 54, 56, 58, 60, 62, 64, 66, 68, and 70 are.
No, 60 is.
The GCF is 4.
68 is divisible by 17 but not by 3.
Well, like any other real number, 68 is divisible by any number except for 0, as division by zero is undefined. 68 is evenly divisible (with no remainder) by: 1; 2; 4; 17; 34; 68 [hope I did not miss any]
no
2,4,1,68
No. 68 is not evenly divisible by 15.
No because 68/13 is 5.23076923
68. 68 is divisible by 17.
3,468
42, 48, 54, and 60 is. -- If it's 'even' then it must also be divisible by 2 . -- If it's divisible by 3 and also by 2, then it must be divisible by 6 . -- The multiples of 6 between 40 and 60 are 42, 48, 54, and 60 .
The answer is (60/68)*100% = 88.235%.
60/4 = 15 Therefore, 60 is divisible by 4.
A number is divisible by 3 if the sum of its digits is divisible by 3. The sum of the digits of 60 is 6 + 0 = 6, which is divisible by 3, so, yes, 60 is divisible by 3. 60 ÷ 3 = 20