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Q: What 3 consecutive numbers have a sum of 39?

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The numbers are 38, 39, and 40.

38; 39; 40!

The numbers are 11, 13 and 15.

48 484 848

33, 36, 39, 42

Yes, the sum of any three consecutive counting numbers has a factor of 3.

Sorry. No sum of even numbers can be an odd number.

The sum of 3 consecutive whole numbers is always equal to 3 times the middle number in that sequence.

38, 39, 40

The numbers are 37, 38, 39 and 40.

The least of the three numbers is 199.

There are no consecutive odd integers whose sum is equal to 35. 9+11+13 = 33, and 11+13+15 = 39.

You probably want to know "What are the 3 consecutive whole numbers whose sum is 72 ?" They are 23, 24, and 25.

It can be, if the numbers are the right ones.

The numbers are 21, 22 and 23.

39

The numbers are 3, 4 and 5.

1,4,5

37+38+39=114

The three consecutive whole numbers you are looking for are 1, 2, and 3. The sum of the first two numbers, 1 + 2 = 3.

the sum of three consecutive numbers is 216. What are the three numbers?

There are no such whole numbers. The sum of three consecutive whole numbers must be a multiple of 3; as 68 is not a multiple of 3 (68 = 3 × 22 2/3) it cannot be the sum of three whole numbers.

The sum of any three consecutive even numbers must be divisible by 3. 32 is not, so there is no solution.

The sum of three consecutive odd numbers must be divisible by 3. As 59 is not wholly divisible by 3 the question is invalid. PROOF : Let the numbers be n - 2, n and n + 2. Then the sum is 3n which is divisible by 3. If the question refers to three consecutive numbers then a similar proof shows that the sum of these three numbers is also divisible by 3. Again, the question would be invalid.

The numbers are 19, 20 and 21.