The expression (7x^2 + 2x + 1) is not a prime trinomial because it can be factored. To determine if it's prime, we can check for factors of the form ((ax + b)(cx + d)). In this case, it does not factor neatly into integers, but it can be analyzed further. In conclusion, while it may not have simple integer factors, it is not prime in the algebraic sense as it cannot be simplified into a product of polynomials.
(2x + 1) (x + 3) = 2x2 + 7x + 3
2x + 5x - 1 = 9x 7x - 1 = 9x -1 = 9x - 7x -1 = 2x -1/2=x
if its 3x3 - 2x + 1 then its a cubic trinomial
(3x - 1) + 7 = (7x - 2x) + x3x - 1 + 7 = 7x - 2x + x3x + 6 = 6x6 = 3xx = 6/3 = 2
5x2+ 7x + 2 = (x + 1)(5x + 2).
(2x + 1) (x + 3) = 2x2 + 7x + 3
(2x + 1)(x + 3) are the factors.
[ x3 + 3x2 + 2x ] is a trinomial. It's factors are [ x, (x + 1), (x + 2) ] .
The factors of 6x2+7x-5 are (3x+5) and (2x-1).
If you mean 2x+4(7x-1) then 2x+28x-4=30x-4=2(15x-2) If you mean 2x+4(7x)-1 then 2x+28x-1=30x-1
7x-1=2x+5 7x-2x=5+1 5x=6 x=6/5=1.2
7 plus 7x--2x plus 3 is: 7 + 7x + 2x + 3 = 0 9x + 10 = 0 9x = -10 x = -10/9 = -1 1/9
2x + 5x - 1 = 9x 7x - 1 = 9x -1 = 9x - 7x -1 = 2x -1/2=x
if its 3x3 - 2x + 1 then its a cubic trinomial
(3x - 1) + 7 = (7x - 2x) + x3x - 1 + 7 = 7x - 2x + x3x + 6 = 6x6 = 3xx = 6/3 = 2
(3x - 4)(x - 1)
5x2+ 7x + 2 = (x + 1)(5x + 2).