If: y = x^2 -2x +4 and y = 2x^2 -4x +4 Then: 2x^2 -4x +4 = x^2 -2x +4 Transposing terms: x^2 -2x = 0 Factorizing: (x-2)(x+0) => x = 2 or x = 0 Therefore by substitution points of intersect are at: (2, 4) and (0, 4)
2x -6 = 4 then 2x = 4 +6 x=10/2 = 5
(x2+3x-4) (x-4)
2x + 7 + 2x = 23 4x + 7 = 23 4x = 16 x = 16/4 x = 4
f(x) = (2x^2 + 5x - 12)/(x + 4) as given, is not defined when the denominator is 0 ie when x + 4 = 0 or x = -4. However, 2x^2 + 5x - 12 = (x + 4)*(2x - 3) so that the function can be simplified to (x + 4)*(2x - 3)/(x + 4) = 2x - 3 This has a zero when 2x - 3 = 0 ie 2x = 3 or x = 1.5
What is X if 2x + 4 = 36 What is X ? 2x + 4 = 36
If X = 4 then 2X = 2 x 4, which is 8
2x-6=4 6+4=2x 10=2x 10/2=x 5=x x=5
2x + x + 4 +2x = x + 20 5x + 4 = x + 20 5x - x = 20 - 4 4x = 16 x = 4
2x + 4 = 16 2x = 16 - 4 2x = 12 x = 12/2 x = 6
4 + x = 2x --> 4 = 2x - x --> 4 = x: x = 4
4 - 2x = 10 -2x = 10-4 -2x = 6 -x = 3 x = -3
If 4x - 2x + 4 = 10, the solution is 2x + 4 = 10 and x = 3.
If 3X - 4 ------ = 0 1-2X-4 So 3X - 4 ----- = 0 [ x (2X-3) ] 2X-3 3X-4 = 2X-3 [ -2X ] X - 4 = -3 [ +4 ] X= 1
2x(x - 4)(x + 4)
2x+4 = -16 2x = -16-4 2x = -20 x = -10
(2x + 4)(2x - 4) to check your answer, use the FOIL method (first, outside, inside, last) F.... 2x x 2x = 4x^2 0.... 2x x -4 = -8x I..... 2x x 4 = 8x L.... 4 x -4 = -16 so 4x^2 - 16 = (2x + 4)(2x - 4)