If you mean 2x+4(7x-1) then 2x+28x-4=30x-4=2(15x-2) If you mean 2x+4(7x)-1 then 2x+28x-1=30x-1
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If: y = x^2 -2x +4 and y = 2x^2 -4x +4 Then: 2x^2 -4x +4 = x^2 -2x +4 Transposing terms: x^2 -2x = 0 Factorizing: (x-2)(x+0) => x = 2 or x = 0 Therefore by substitution points of intersect are at: (2, 4) and (0, 4)
2x -6 = 4 then 2x = 4 +6 x=10/2 = 5
2x + 7 + 2x = 23 4x + 7 = 23 4x = 16 x = 16/4 x = 4
(x2+3x-4) (x-4)
f(x) = (2x^2 + 5x - 12)/(x + 4) as given, is not defined when the denominator is 0 ie when x + 4 = 0 or x = -4. However, 2x^2 + 5x - 12 = (x + 4)*(2x - 3) so that the function can be simplified to (x + 4)*(2x - 3)/(x + 4) = 2x - 3 This has a zero when 2x - 3 = 0 ie 2x = 3 or x = 1.5