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5y + (4 - 2y) = 9 5y + 4 - 2y = 9 3y + 4 = 9 3y = 5 y = 5/3
5y - 4 + 9y - 1y + 15= 5y + 9y - 1y + 15 - 4= (5 + 9 - 1)y + (15 - 4)= 13y + 9
(x + 4) + (x + 5) = 2x + 9
5y = 2y+9 5y-2y = 9 3y = 9 y = 3
Simultaneous Equations. 4x + 5y = 51 4x - 5y = 21 eliminate 'y' by addition. Hence 8x = 72 x = 72/8 x = 9 When x = 9 Substitute into eith equation. 4(9) + 5y = 51 36 + 5y = 51 5y = 51 - 36 5y = 15 y = 3 Hence the answer is ( x,y) = ( 9,3).
I assume you mean find Y and then add it to 4. 5Y - 8 = 37 add 8 to each side 5Y = 45 divide both sides by 5 Y = 9 ( it checks by inspection; so....) 9 + 4 = 13
Solving for y: 5y = 9 + 2y 5y - 2y = 9 3y = 9 y = 9/3 = 3
The x-intercept is the point where the y-intercept is zero. "3x 5y 9" is not an equation. 3x+5y+9, or 3x-5y+9, are examples of what was meant to be shown.
40 + 9 = 5y + 9 Since 9 is present on both sides of the equation,therefore we can strike it off on both sides,the remaining equation being 40 = 5y or 5y = 40 5y = 40 or y = 40/5 Therefore,y = 9 .
14
y=4
yes it is..your welcome