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The probability of drawing a particular color is the number of blocks that color, over the total number of blocks. Since these are disjoint events, the solution is the product of the two probabilities of the draws. So: P(red, blue) = P(red) * P(blue) = (3/10) * (5/10) = 15/100 or 3/20
A rectangle that is colored blue.
There are an infinite number of possible shades. Each shade of blue can be modified slightly by adding a new colour, the possibilities are endless. As far as we know, there are more than fifty thousand shades of blue. Air Force Blue, Celeste, Egyptian blue, Maya Blue, Royal Blue, and Ultramarine are a few.
Red, blue, green or yellow.Red, blue, green or yellow.Red, blue, green or yellow.Red, blue, green or yellow.
No, it will not. Methylene blue agar is used to identify gram negative bacteria, staphylococcus is gram positive.
Polluted water sample will decolorize the methylene blue solution faster than a pure water sample.
The dyes (eosin Y and methylene blue) inhibit the growth of gram- positive bacteria.
The Eosine Methylene Blue test is selective for only gram-negative bacteria. It is possible for gram-positive bacteria to grow, but it would barely grow. Staphylococcus are gram-positive spherical bacteria. So it would not grow on the Eosine methylene Blue Agar.
Adding methylene blue to sugar water solution.
It is used in gram staining to differentiate gram negative and gram positive bacteria. After being dyed, the cells are washed with ethanol. Gram positive bacteria will retain the methylene blue due to the amount of peptidoglycan in their cell walls, where gram negative cells will not. Iodine is used as a counter stain, which is up-taken by gram negative cells. After the gram staining procedure is finished, gram positive cells will appear dark purple or blue due to the retained methylene blue. Gram negative cells will appear pink or red due to the iodine counter stain.
because it is acidic?
Methylene blue is a stain used in microbiology. The dye attaches to the object, which allows what would normally be fairly see-through to be visible to the microscope.
do not know