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it wouldn't equal anything its a prime number but of course it would be only 2x1
Move each point with the coordinates (a, b) to the location (b, -a).Equivalently, if the points are represented by a 2x1 column matrix, then pre-multiply by the matrix ( 0 1) (-1 0)
One way to solve this system of equations is by using matrices. Form an augmented matrix in which the first 2x2 matrix is the coefficient matrix and the 2x1 matrix on its right is the answer. Now apply Gaussian Elimination and back-substitution. Using this method gives x=5 and y=1.
2x1=1 so 1-Y=0 so Y=0, was this really a question?
2x1=2
The determinant is only defined for square matrices.
it doesnt have an inverse since only square matrices have an inverse
inverse matrix. x1+x2+x3=3,000 -x1+5x2=0 2x1-3x3=0.
it wouldn't equal anything its a prime number but of course it would be only 2x1
2x1 = 2x
2
There is no number that if you multiply it by the same number will equal 2. only 2x1 is the only multiplyed number that will equal 2.====================================You both might like to play around with 1.414214 for a while.
There are 4 ways to do it. You can graph, use substitution, use elimination, or use matrices. Graphing: Graph the two equations and the coordinates where they intersect are the answer. Substitution: Solve one of the equations for one of the variables and substitute that in the other equation. Then you'll find the value of that variable and you can substitute that and get the other variable. Elimination: Make the coefficients of one of the variables opposites of each other and then add both equations. The opposites will cancel and you have the other variable. Then when you find that variable, find the other one by substituting the number for that variable in one of the equations. Matrices: Make sure both equations are in standard form (Ax+By=C). Then make a 2x2 matrix that has the coefficients of x in the left column and the coefficients of y in the right column and each equation gets its own row. Then make a 2x1 matrix with the C values. Put the C value of the equation you put at the top at the top and the other one at the bottom. Then multiply the inverse of the 2x2 matrix by the 2x1 matrix and you'll get a 2x1 matrix with x at the top and y at the bottom.
Move each point with the coordinates (a, b) to the location (b, -a).Equivalently, if the points are represented by a 2x1 column matrix, then pre-multiply by the matrix ( 0 1) (-1 0)
it can only be made by multiplying 2x1 or 1x2
Move each point with the coordinates (a, b) to the location (b, -a).Equivalently, if the points are represented by a 2x1 column matrix, then pre-multiply by the matrix ( 0 1) (-1 0)
One way to solve this system of equations is by using matrices. Form an augmented matrix in which the first 2x2 matrix is the coefficient matrix and the 2x1 matrix on its right is the answer. Now apply Gaussian Elimination and back-substitution. Using this method gives x=5 and y=1.