No. The slope of the distance-time graph is the change in distance per unit of time - otherwise known as speed. Acceleration is the slope of the speed time graph.
acceleration
The constant acceleration
Equal to the acceleration of the object that is moving through distance in time. * * * * * No. The slope of the distance-time graph is the change in distance per unit of time - otherwise known as speed.
The slope of a line on a velocity-time graph is acceleration.
Acceleration.
If the graph is a straight line, then the slope of the line is the average acceleration of the ball.
This depends on what the graph represents. If it is a graph of velocity on the vertical and time on the horizontal, then if acceleration is at a constant rate, the graph will be a straight line with positive slope (pointing 'up'). If acceleration stops, then the graph will be a horizontal line (zero acceleration or deceleration). If it is deceleration (negative acceleration), then the graph will have negative slope (pointing down).
The slope of a line on a distance-time graph represents the speed or velocity. The steeper the line is and the greater the slope of the line is, the faster the object is moving.
No. The slope on a speed vs time graph tells the acceleration.
Speed = distance / time A line graph with distance on the vertical axis and time on the horizontal axis could be used to determine speed. The speed would equal the slope of the line. Alternatively, a line graph with distance/time on the vertical axis and time on the horizontal axis would show speed. The acceleration would equal the slope of the line.
In general, nowhere, because acceleration is the second derivative of distance with respect to time. However, in the special case of a constant acceleration, the acceleration will be twice the slope of the line, since distance = 0.5 * time squared.
A graph that shows speed versus time is not an acceleration graph.The slope of the graph at any point is the acceleration at that time.A straight line shows that the acceleration is constant.