Q: Is drawing marbles from a bag without replacing them dependent or independent?

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If you draw one out, replace it, and draw another out, it's independent. If you draw one out, DON'T replace it, and draw another out, it's dependent. (Similarly if you draw them both out at the same time.)

The second and third marbles depend upon the first, so they are dependent. Even if they are all being drawn together, because there is no replacement, each removal affects the original group of marbles.

7/15 for blue marbles and 8/14 for the purple marbles this is dependent probability

The first marble is the independent event because its probability is only based on the sample space of the bag. The second marble is the dependent event because its probability is based on the sample space of the bag which has now been changed by the first marble.

Probability of drawing a blue marble first is 4 in 8 (or 50%) Probability of drawing a blue marble second is 3 in 7 (or 42.85714%) Probablility of drawing blue then blue is the two above multiplied 0.5 * 0.4285714 Which is 0.212142407 or 21% or One in Five.

Related questions

If you draw one out, replace it, and draw another out, it's independent. If you draw one out, DON'T replace it, and draw another out, it's dependent. (Similarly if you draw them both out at the same time.)

The answer is dependent on whether of not you replace the marbles in the jar. If you do, the probability of drawing a red marble is 9 in 15 or 60%, every time. If you do not replace the marbles, the probability of drawing a red marble is 2 in 8 or 25%.

The second and third marbles depend upon the first, so they are dependent. Even if they are all being drawn together, because there is no replacement, each removal affects the original group of marbles.

7/15 for blue marbles and 8/14 for the purple marbles this is dependent probability

Since the box contains 16 marbles, seven of them white, then the probability of drawing one white marble is 7/16. If you replace the marble and draw again, the probability of drawing another white marble is still 7/16. The net probability of drawing two white marbles, while replacing the first, is 49/256.

There are a total of 25 Marbles The chances are 3 out of 25 drawing a Red marble. 3/25 = 12% chance of drawing a red marble

25%

The first marble is the independent event because its probability is only based on the sample space of the bag. The second marble is the dependent event because its probability is based on the sample space of the bag which has now been changed by the first marble.

25

Probability of drawing a blue marble first is 4 in 8 (or 50%) Probability of drawing a blue marble second is 3 in 7 (or 42.85714%) Probablility of drawing blue then blue is the two above multiplied 0.5 * 0.4285714 Which is 0.212142407 or 21% or One in Five.

3 in 10

Suppose probability of drawing a red marble is p. Then p = 2*(1 - p) that is p = 2 - 2p or p = 2/3 So 2/3 of the 24 marbles are red 24*(2/3) = 16 red marbles.