Probability of drawing a blue marble first is 4 in 8 (or 50%)
Probability of drawing a blue marble second is 3 in 7 (or 42.85714%)
Probablility of drawing blue then blue is the two above multiplied 0.5 * 0.4285714
Which is 0.212142407 or 21% or One in Five.
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The probability of drawing a red card followed by a spade is (1 in 2) times (1 in 4), or 1 in 8, or 0.125. The probability of drawing a spade followed by a red card is (1 in 4) times (1 in 2), or 1 in 8, or 0.125. Since you have two distinct desired outcomes, add them together, giving a probability of drawing a red card and a spade of 0.25.
There are 9+6 = 15 checkers in the bag. 6 of them are red. 6 out of 15 are red. Drawing a red checker has a probability of P = 6/15 = 2/5 = 0.4 = 40% Since you replace the checker, the probability Q that red is drawn again remains 0.4. The probability of both events occurring (red drawn twice) equals the product of probabilities, PQ = (0.4)*(0.4) = 0.16.
Probability of not drawing an ace equals one minus the probability of drawing an ace. The probability of drawing an ace is 4/52 or 1/13. So the probability of not drawing an ace on one draw is 1 - 1/13 or 12/13 or 0.9231 (92.31%).
The probability of drawing the first face card is 12 in 52. The probability of drawing the second is 11 in 51. The probability of drawing the third is 10 in 50. Thus, the probability of drawing three face cards is (12 in 52) times (11 in 51) times (10 in 50) or (1320 in 132600) or about 0.009955.
4 out of 25
Since the box contains 16 marbles, seven of them white, then the probability of drawing one white marble is 7/16. If you replace the marble and draw again, the probability of drawing another white marble is still 7/16. The net probability of drawing two white marbles, while replacing the first, is 49/256.
The probability of drawing two reds, with replacement, is the same as the probability of drawing a red, times itself. So: P(drawing two reds) = P(drawing a red)2 = (12/(2 + 12 + 6))2 = (12/20)2 = (3/5)2 = 9/25
It is approx 0.44
The probability of drawing a king is 4:52The probability of drawing a diamond is 13:52 (or 1:4)The probability of drawing a king (0.07692...) then replacing that king into the deck then drawing a diamond is 0.019230769.If you leave the king out, the probability will be slightly greater (4/52) * (13/51)Unless the king you left out of the deck was a king of diamonds, in which case, the probability would be (4/52) * (12/51)
The answer is 1/169.
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What is the probability that the second tile you pick is yellow? (didnt have enough space to finish the question)
No, it is the same.
The probability of drawing a diamond from a standard 52-card poker deck without jokers is 13/52, or 1/4. The probability of drawing a second diamond at that point would then be 12/51, for an overall probability of 12/212, or 3/53. This amounts to about a 5.88% chance.
The probability of drawing a red card followed by a spade is (1 in 2) times (1 in 4), or 1 in 8, or 0.125. The probability of drawing a spade followed by a red card is (1 in 4) times (1 in 2), or 1 in 8, or 0.125. Since you have two distinct desired outcomes, add them together, giving a probability of drawing a red card and a spade of 0.25.
There are 9+6 = 15 checkers in the bag. 6 of them are red. 6 out of 15 are red. Drawing a red checker has a probability of P = 6/15 = 2/5 = 0.4 = 40% Since you replace the checker, the probability Q that red is drawn again remains 0.4. The probability of both events occurring (red drawn twice) equals the product of probabilities, PQ = (0.4)*(0.4) = 0.16.