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Q: What 2 digit number has a remainder of 3?

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You can't have a remainder of 6 when you divide by 2! JHC!

2

1.5

62

It is 997.

mathematics

-3

111

Regardless of the dividend (the number being divided), no divisor can produce a remainder equal to, or greater than, itself..... dividing by 4 cannot result in a remainder of 5, for example, Therefore the only single-digit number which can return a remainder of 8 is 9. 35 ÷ 9 = 3 and remainder 8

62

The simplest answer is 10124 divided by 125.

103

0.4286

99

A smaller 3 digit number or a 2 digit number (99).

27.3333

The nth triangular number is given by ½ × n × (n+1)→ the 5857th triangular number is ½ × 5857 × 5858 = 17,155,153, so its units digit is a 3.------------------------------------------------------------Alternatively,If you look at the units digits of the first 20 triangular numbers they are {1, 3, 6, 0, 5, 1, 8, 6, 5, 5, 6, 8, 1, 5, 0, 6, 3, 1, 0, 0}At this stage, as we are only concerned with the units digit, as we now have a 0 for the units digit, when 21 is added it is the same as adding 1 to 0 to give a 1, for the 22nd triangular number, we are adding 2 to the 1 to give 3, and so on - the sequence of 20 digits is repeating.To find the units digit of the nth triangular number, find the remainder of n divided by 20 and its units digit will be that digit in the sequence (if the remainder is 0, use the 20th number). To find the remainder when divided by 20 is very simple by looking at only the tens digit and the units digit:If the tens digit is even (ie one of {0, 2, 4, 6, 8}), the remainder is the units digitIf the tens digit is odd (ie one of {1, 3, 5, 7, 9}), the remainder is the units digit + 10.5857 ÷ 20 = ... remainder 17; the 17th digit of the above sequence is a 3, so the units digit of the 5857th triangular number is a 3.This trick can be used for much larger triangular numbers which calculators cannot calculate exactly using the above formula. eg the units digit of the 1234567890123456789th triangular number is... 1234567890123456789 ÷ 20 = .... remainder 9, so this triangular number's units digit is the 9th digit of the above sequence which is a 5.

Any two digit number that fits the formula 3n+1 For example if n=4, 3x4+1=13 which fits your question.

First note that when you divide any number by the 10, the remainder will be the same number as the units digit. For example, when 26 is divided by 10, the remainder is 6 and when 37832728 is divided by 10, the remainder is 8. For this problem, we just need to know what the units digit of the number 2^400. So let's see if we can see a pattern. 2^1 = 2, 2^2 = 4, 2^3 = 8, 2^4 = 16, 2^5 = 32, and 2^6 = 64. The pattern we are looking for is the value of the units digit. It is 2, 4, 8, 6, 2, 4, 8, 6, and it repeats. Every fourth remainder is 8 and since 400 is a multiple of 4, 2^400 will have 6 as its units whatever the number is and therefore the remainder will be 6. Hope that helps :)

No. When adding the smallest 2 digit number (= 10) to the smallest 2 digit number (again, 10) the result is a 2 digit number (10 + 10 = 20). When adding the largest 2 digit number (= 99) to the largest 2 digit number (again, 99) the result is a 3 digit number (99 + 99 = 198). As you can see, you'll either get a 2 or 3 digit number, but never a 4 digit number.

0.2308

2,5 or 8

2. To test a number to be divisible by 3, add up the digits and if the sum is divisible by 3, so is the original number. If not, the excess over a multiple of 3 gives the remainder when the original number is divided by 3. Subtract this remainder from 3 and this gives the smallest digit to replace the blank; unless the remainder is 0, in which case the blank can be replaced by a 0: 8 + 6 + 9 + 3 + 5 = 31 → 31 ÷ 3 = 10 remainder 1 Replace blank by 3 - 1 = 2: 826935 is divisible by 3

When you divide 1387 by 2 you get a remainder of 1, so it is odd. A number ending (least significant digit) in a odd number digit like 1, 3, 5, 7, and 9 is odd. A number ending (least significant digit) in a even number digit like 0, 2, 4, 6, and 8 is even.* * * * *Nearly correct!An integer ending in 1, 3, 5, 7 and 9 is odd and an integer ending in 0, 2, 4, 6, 8 is even. The concept of odd and even does not apply to decimal fractions.When you divide 1387 by 2 you get a remainder of 1, so it is odd. A number ending (least significant digit) in a odd number digit like 1, 3, 5, 7, and 9 is odd. A number ending (least significant digit) in a even number digit like 0, 2, 4, 6, and 8 is even.

Yes, unless the 3 digit number is negative, or a decimal.