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Q: Is is 1023 divisible by 2?

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1, 3, 11, 31, 33, 93, 341, 1023

No, 1023 it is not one of the multiples of the base 2 (binary) system. 1024 is. 1024 = 210. Of course 1023 can be represented in base 2 however as 1111111111.

no.. for example 6,12,18 are divisible by 2..but not divisible by 8.

2 is not divisible by 972. 972 is divisible by 2.

2 is not divisible by 92. 92 is divisible by 2.

2 is not divisible by 19008. 19008 is divisible by 2.

2 is not divisible by 342. 342 is divisible by 2.

2 is not divisible by 870. 870 is divisible by 2.

2 is not divisible by 180. 180 is divisible by 2.

351 is not divisible by 2. 2 is not divisible by 351.

416 is divisible by 2 but is not divisible by 3.

Of course not ! The answer is right within your question: 2 is divisible by 2 but 2 is not divisible by ... (can you dig it ?)

No because to be divisible by six, a number must be divisible by 2 and 3 and it is not divisible by 2.

True. Since 6 is divisible by 2, any number that is divisible by 6 will automatically be divisible by 2.

The last digit of 22 is '2' which is even (divisible by 2) so 22 is divisible by 2.

402 is divisible by 2.402 is divisible by 2.402 is divisible by 2.402 is divisible by 2.

No. But 6,434 is divisible by 2 .

No. But 2,360 is divisible by 2 .

No. 864 is divisible by 2.

269,747 is not divisible by 2.

No, 58462 is divisible by 2.

No, but 504 is divisible by 2.

No, 66 is divisible by 2.

Even numbers are divisible by 2.

No, but 90 is divisible by 2.