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Yes and here is why. The sum of the exterior angles of a regular polygon of n sides is 360°. Each exterior angle measures 360°/n. So we need to find a natural number n such that 360/n=30 and that n will be the number of angles in the polygon. 360/n=30 360=30n 360/30=n so n would need to be 12 and a 12 sided regular polygon has each exterior angle of measure 30 degrees.

Q: Is it possible for the exterior angles of a regular polygon to measure 30 degrees?

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If it's a regular polygon then each exterior angle measures 36 degrees

The sum of the exterior angles of a polygon = 360360 / 36 = 10 degrees

A regular polygon will have 360 sides with exterior angles of 181 degrees.

The sum of the exterior angles of ANY polygon is 360 degrees.

The sum of the exterior angles of any polygon must be 360 degrees.360/8 = 45 degrees

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The exterior angles of any polygon add up to 360 degrees

The sum of the exterior angles of a polygon, whatever the measure of each one, is always 360 degrees.

The exterior angles add up to 360 degrees

Providing that it's a regular polygon then each exterior angle will measure 12 degrees.

The sum of the exterior angles of a polygon = 360360 / 36 = 10 degrees

If it's a regular polygon then each exterior angle measures 36 degrees

360 degrees

Each exterior angle will measure 11.25 degrees.

There can be no such polygon. The sum of the exterior angles of ANY polygon is 360 degrees. If it is a regular polygon, then the number of angles MUST divide 360 degrees. Since 18.95 does not divide 360, there cannot be such a polygon. If the exterior angle was 18.94737... degrees, it would be a 19-sided polygon.

A regular polygon will have 360 sides with exterior angles of 181 degrees.

The sum of the exterior angles of ANY polygon is 360 degrees.

The sum of the exterior angles of ANY polygon is 360 degrees.