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Given an interior angle how do you find the sum of exterior angles of a polygon?
Given a shape as such... ______________________________________ / A=72 B=65 \ \ / \_C=105__________________D=110_______/ (sorta) You take the interior angles that you have and subtract them from 360 to get their supplementary angles, which would be the measure of the outside angles corresponding to the interior angles Measure of <A= 72- so 360- 72=288*; so the measure of the exterior angle corresponding to <A is 288* You can do the same thing for the rest of the angles in the polygon. Hope it helps...
What is the formula to find the sum of exterior angles of a polygon?
it always equals to 360
What is The sum of the exterior angles of a docegon?
I think its this.... Find the interior. Then do 180 - the interior. That is the exterior. * * * * * The correct answer is that the sum of the exterior angles of any polygon is always 360 degrees.
Find the sum of the measure of the exterior angles of a 25 gon?
4140Improved Answer:-Exterior angles = 360 degreesInterior angles = 4140 degrees
Measure of an exterior angle of a 12-gon?
To find an exterior angle of a regular 12-gon, use the formula to find the total sum of all the angles first: total sum of all angles = (n-2)*180where 'n' is the number of sides, or 12.By solving, you will find that the total sum of all angles is 1800 degrees, so since it is a regular polygon, you can divide by 12 to find the measure of each interior angle, which is 150 degrees.Once you know the measure of the interior angles, since an exterior angle is the supplement of an interior angle, subtract 150 degrees from 180 degrees (the measure of a straight line) to find the exterior angles, which will be 30 degrees.
