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It is impossible. 2 is the only Prime number that is even, all other even numbers are divisable by 2 and therefore not prime. In order to get a remainder of two when dividing by 4, the number must be divisable by 2 but not four. Therefore, any prime number that is divided by 4 would have a remainder of either 1 or 3.

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What can be the largest possible remainder if the divisor in a given division problem is 48?

The remainder is the number that is left over after the initial value has been divided as much as it can. If any numbers greater than 48 were present as a remainder, then these could be divided further into 48. If 48 is present as the remainder, then this can be divided by 48 to give 1, leaving no remainder. Thus, the largest possible remainder if the divisor is 48 is 47.


Is it possible for the remainder in a division problem to be greater than the divisor?

If it is divided by a fraction or a decimal. Like 1/5 or .986


What is greatest possible whole number remainder if you divide any number by W explain.?

It is W - 1. If the remainder is greater than or equal to W, then you can subtract W from the remainder and increase the quotient by 1.


What is the least prime number greater than 25 that will have a remainder of 2 when divided by 25?

127 is the least prime number greater than 25 that will have a remainder of 2 when divided by 25.


What is the remainder of 3 divided by 115?

0.0261


Can a remainder be greater than the dividend?

Absolutely not possible


What number is greater than hundred and can be divided by four and no remainder?

104.


When your number is divided 7the remainder is 3 When your number is divided by 5the remainder is 4Find your number if it is greater than 10 but less than 50?

24 is answer.


The smallest positive integer that is greater than 100 and leaves a remainder of 1 when divided by 3 a remainder of 2 when divided by 5 and a remainder of 3 when divided by 7?

The integer is 157. 157/3 = 52 remainder 1 157/5 = 31 remainder 2 157/7 = 22 remainder 3


The questions asks When a number is divided by 32 what is the greatest value the remainder may have?

When a number is divided by 32, the remainder can range from 0 to 31, as the remainder can never be greater than the divisor. Therefore, the greatest value the remainder may have is 31.


What is the largest remainder possible if a number is divided by 9?

The largest remainder would be 8, because if it were 9 you could divide the number once more. The largest remainder you can have is always one less than what you're dividing by. So if you're dividing by 10, your largest remainder is 9. If you're dividing by 100, it's 99. And so on.


Explain why 2 is the only even number?

Any even number greater than 2 can be divided by 2 without remainder. It is, therefore, a composite number, not a prime.