It is impossible. 2 is the only Prime number that is even, all other even numbers are divisable by 2 and therefore not prime. In order to get a remainder of two when dividing by 4, the number must be divisable by 2 but not four. Therefore, any prime number that is divided by 4 would have a remainder of either 1 or 3.
The remainder is the number that is left over after the initial value has been divided as much as it can. If any numbers greater than 48 were present as a remainder, then these could be divided further into 48. If 48 is present as the remainder, then this can be divided by 48 to give 1, leaving no remainder. Thus, the largest possible remainder if the divisor is 48 is 47.
If it is divided by a fraction or a decimal. Like 1/5 or .986
It is W - 1. If the remainder is greater than or equal to W, then you can subtract W from the remainder and increase the quotient by 1.
127 is the least prime number greater than 25 that will have a remainder of 2 when divided by 25.
0.0261
Absolutely not possible
104.
24 is answer.
The integer is 157. 157/3 = 52 remainder 1 157/5 = 31 remainder 2 157/7 = 22 remainder 3
When a number is divided by 32, the remainder can range from 0 to 31, as the remainder can never be greater than the divisor. Therefore, the greatest value the remainder may have is 31.
The largest remainder would be 8, because if it were 9 you could divide the number once more. The largest remainder you can have is always one less than what you're dividing by. So if you're dividing by 10, your largest remainder is 9. If you're dividing by 100, it's 99. And so on.
Any even number greater than 2 can be divided by 2 without remainder. It is, therefore, a composite number, not a prime.