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Yes, two even numbers added together will always equal an even number. picture this: you have 8 people, they each have a pair, they are even. Then you add an even number that has partners. So all of them will have a partner and be even.

HOPE THIS HELPED!!!

, Jenna

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Q: Is it true that the sum of two even numbers is never odd?
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Related questions

Is it not true that the sum of two even numbers is never odd?

It is true that the sum of 2 even numbers is never odd


Why does to even numbers equal a odd number?

What! Even numbers never equal an odd number. Not ever!


Irrational numbers are said to be never odd or even?

Yes, irrational numbers are neither odd nor even.


Can product of 2 odd no be even?

The product of two odd numbers is never even.


When does an even number of odd numbers equal an odd number?

Never. When you dont add the same odd number and even number of times. For example: 5 + 3 (2 odd numbers; and even amount of odd numbers ) = 8 5 + 3 + 7 = 15 an odd amount of odd numbers 5 + 3 + 7 + 9 = 24 another even amount of odd numbers. But never if you use the only same number


Can the GCF of an odd number and an even number ever be even?

No. Odd numbers don't have even factors.


If the product of 2 even numbers is even then the 2 numbers must be even?

This is not always true. If the sum of two numbers is even, then those two numbers are either both even or both odd. For example: 2 + 2 = 4 (even + even = even) 5 + 7 = 12 (odd + odd = even) 3 + 2 = 5 (odd + even = odd)


Is the gcf of a odd number and an even number always even?

The GCF of an odd and even number is never even.


Is it true that any 2 odd numbers can be even?

yes


The sum of three odd numbers is always odd true or false?

The sum of three whole odd numbers will always be odd keeping in mind that zero is neither even nor odd and that 'null' is not a number.


What 3 odd numbers can equal 16?

Adding three odd numbers will never equal an even number.


Is the gcf of 2 odd numbers alway an even number?

That can never be an even number.