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Q: Is one divide by square root of three a surd?

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A surd is the square root of an integer (whole number), e.g. square root of 2 is a surd. Pi is not the square root of an integer so not a surd, just an irrational number

[square root (78)] squared = 78. There is not a surd from for an integer.

If the value of the surd is positive, then it will be another surd. Otherwise it will be a complex number.

Yes the square root of 2 is a surd which is an irrational number that can't be expressed as a fraction.

no

The square root of 82 cannot be reduced as a surd.

Surds are irrational numbers and 27 is a rational number but if you mean the square root of 27 then it is an irrational number and expressed as a surd it is 3 times square root of 3.

Yes.

yes

Yes

Not as a simplified surd, if that is what you mean.

8

Yes. A surd is any irrational number that can be expressed as the root of another number. As pi is a number, although it is a transcendental and hence irrational, the square root of pi is still an irrational number that can be expressed as the square root of another number.

A surd in the form aâˆšb cannot, in general, be simplified.

Expressed as a surd, the square root of 28 is equal to 2 root 7.

No because it is 3

A surd is an irrational number that can't be expressed as a fraction as for example the square root of 2

Expressed as a surd, the square root of 448 is equal to 8 sqrt(7).

Expressed as a surd, the square root of 1/7 is equal to sqrt(7)/7.

The square root of eight is an irrational real number.

An irrational number such as the square root of 2

Expressed as a surd, the square root of 2/5 is equal to sqrt(10)/5. Expressed as a decimal number, rounded to three decimal places, this is equal to 0.632.

Infinite surd is a term used in mathematics. The definition of an infinite surd is a never ending irrational number with an exact value that would be left in square root form.

Expressed as a surd, sqrt(75) + sqrt(48) = 9 sqrt(3).

Expressed as a surd, sqrt(98) + sqrt(2) = 8 sqrt(2).