No because it is 3
[square root (78)] squared = 78. There is not a surd from for an integer.
If the value of the surd is positive, then it will be another surd. Otherwise it will be a complex number.
no
Yes
Yes. A surd is any irrational number that can be expressed as the root of another number. As pi is a number, although it is a transcendental and hence irrational, the square root of pi is still an irrational number that can be expressed as the square root of another number.
'pi' is not a 'surd' because it is not a 'square root' of any number. 'pi' is an IRRATIONAL number. Irrational numbers are those were the decimals go to infinity AND the decinal digits are not in any regular order. pi = 3.141592654.... (recur to infinity and no regular order0. 'pi' in surd form is sqrt(pi) = sqrt(3.141592654....) = 1.772453851..... (which is also irrational). In school/college etc., you are given 'pi = 3.14 , 3.1416 , 22/7' Tese are only APPROXIMATIONS for ease of calculating. 'Super Dupa' computers have calculated 'pi' to at least 50 billion places and still going. NB A decimal number such as 1.33333.... is NOT irrational. It is RATIONAL , because it can be converted to a ration/quotient/fraction. Irrational numbers cannot be converted to an exact value 'ratio/quotient/fraction'. Notice the decimal digits are in a regular order of '3'....
[square root (78)] squared = 78. There is not a surd from for an integer.
If the value of the surd is positive, then it will be another surd. Otherwise it will be a complex number.
no
Expressed as a surd, sqrt(75) + sqrt(48) = 9 sqrt(3).
Yes the square root of 2 is a surd which is an irrational number that can't be expressed as a fraction.
YES!!! sqrt(8) - 2*sqrt(2) NB '*' means 'Multiply'.
Yes
Yes.
The square root of 82 cannot be reduced as a surd.
A surd in the form a√b cannot, in general, be simplified.
The square root of eight is an irrational real number.