No
is the number 7 in real math a whole number
The square root of 17 lies between the whole numbers 4 and 5. This is because (4^2 = 16) and (5^2 = 25), so (\sqrt{17}) is greater than 4 but less than 5. Therefore, (\sqrt{17}) is approximately 4.123.
425 = 25 x 17 Hence sqrt(425) = sqrt(25 x 17) => sqrt(25) x sqrt(17) => 5sqrt(17) in Surd form Since '17' is a prime number, then its square root is irrational and an approximation is ~ 4.123105626.... Hence 5(4.123105626....) ~= 20.61552813.... is the irrational number for the square root of 425.
Yes, 17 is a whole number.
GM(5, 10) = sqrt(5*10) = sqrt(50) = 7.1 approx So, to the nearest whole number, the answer is 7.
(±4)2 = 16 < 17 < 25 = (±5)2 so -5 < sqrt(17) < -4 and 4 < sqrt(17) < 5
Examples of such numbers are 49, where sqrt(49) = 7, 81, where sqrt(81) = 9. Such numbers are called square numbers.
-11 < sqrt(117) < -10 and 10 < sqrt(117) < 11
sqrt(39) = ±6, to the nearest whole number.
It is 17 to the nearest whole number.
sqrt(156) = 12.489996 (rounded)Rounded to the nearest whole number, that's 12.
sqrt(17.000.000) = sqrt(1.000.000) * sqrt(17) = 1000 * sqrt(17) = 1000 * 4,123156(..) = 4123,156(..)