Yes and it ends up being 730.
It is: 3650/5 = 730
Yes Any number ending in 5 or 0 is divisible by 5 730 x 5 = 3650
True. Since 615 ends in 5, it is divisible by 5. Since the sum 12, of the digits of 615, is divisible evenly by 3, 615 is divisible by 3.
no because 5,15,25,35,45,55,65,75,85,95,105...are not divisible by 10.10,20,30,40,50,60,70,80,90,100 are divisible by 10 and 5
Yes, it is true 558/3 = 186 To find out if a number is divisible by 3, add the digits; if the sum is divisible by 3, so is the number 5+5+8 = 18 which is divisible by 3
730
It is a TRUE statement.
1, 2, 5, 10, 25, 50, 73, 146, 365, 730, 1825, 3650
455 can go into 5 approximately 91 times.
Three is a prime number and isn't divisible by any whole number * * * * * True, but irrelevant to the question. Any number that is divisible by 10 MUST be divisible by 5. Therefore there are no such numbers.
1, 2, 5, 10, 25, 50, 73, 146, 365, 730, 1825, 3650 2, 5 and 73 are prime.
50% of numbers divisible by 5 are even, the other 50% are odd. If the single's digit of a number is 5, then the number is divisible by 5 and odd. For example, 25. However, if the single's digit of a number is 0, then the number is divisible by 5 and even. For example, 20.