No, an iceberg is approximately 10% less dense than seawater. This is why it floats
Yes. The rule of thumb is 20 percent is visible above the water. Yes, they do float, however i believe that it's 10% that is visible due to the density of ice (0.9 g/cm) and the density of water (1g/cm). So .1 or 1 tenth of the iceberg is above the surface. (10%)
Sea-Water doesn't freeze
Seawater does not have a density of 5.
Any object that is floating will displace a mass of fluid equal to the mass of the floating object. Since the density of an iceberg is about 90% of the density of seawater most of the iceberg will be under water to create enough buoyancy to support the bit above the water. About 10% will be above the water. Pure ice has a density of about 916.7 kg/m³. Surface seawater has a typical density of about 1027 kg/m³. We can use these figures to work out that 1m³ of ice has a mass of 916.7kg. The amount of seawater that needs to be displaced to support this ice is 916 ÷ 1027 = 0.892m³. Since any object that is floating will displace a mass of fluid equal to the mass of the floating object we know that our 1m³ iceberg will have 0.892m³ under the water and 0.108m³ above the water. i.e. 89.2% underwater and 10.8% above the water. The percentages will be the same for any size iceberg. Since the density of Sea Water can vary and icebergs are not completely pure water there will be a bit of variation from these figures, a figure of 10% is normally used.
I would expect it to have more or less the same density, since it is made of the same material.
Yes. The rule of thumb is 20 percent is visible above the water. Yes, they do float, however i believe that it's 10% that is visible due to the density of ice (0.9 g/cm) and the density of water (1g/cm). So .1 or 1 tenth of the iceberg is above the surface. (10%)
The density of seawater increases if salinity increases.
The average density of pure ice is about 920 kg/m³. The average density of seawater is about 1025 kg/m³. By Archimedes's principle, the mass of the seawater displaced (i.e. the amount of the iceberg underwater) should equal the mass of the iceberg. Using that principle, for each 1 m³ of seawater displaced it takes 1025 kg of ice - which will have a volume of 1025 kg x 1 m³/920 kg = 1.114 m³. In other words, 1m³ of the iceberg is submerged for every 1.114 m³ of iceberg. 1/1.114 = 0.89756 So, on average about 90% of the iceberg is submerged. If the seawater is a little less salty, more of the iceberg is submerged. If the iceberg is "dirty" - with stuff in it that is more dense than ice, more of the iceberg is submerged. If the iceberg has voids (air pockets) it will be less dense and less of the iceberg is submerged.
Sea-Water doesn't freeze
Density currents - more dense seawater sinking beneath less dense seawater.
Relative salinity is the most important factor in seawater density.
79% of an iceberg is underwater, so 21% or about one fifth is above it. However given the shape and size of an iceberg, as little as 10% can be above water at times, so it can be between one tenth and one ninth above water.
the salt makes seawater denser than freshwater. more salt increases the density
the answer to this question is a density current forms when more dense seawater sinks beneath less dense seawater
the answer to this question is a density current forms when more dense seawater sinks beneath less dense seawater
Approximately 9/10 of an iceberg is below the water. The figure is approximate because the density of the berg depends on how must the ice is compacted and how much air it contains. It also depends on the density of the seawater which, in turn, depends on its salinity and temperature.
the answer to this question is a density current forms when more dense seawater sinks beneath less dense seawater