Yes, because when you divide you divide the # outside of the braket which is the dividend.
The dividend is inside, the divisor is outside, and the answer is the quotient.
In the equation, it's the answer inside the "box". The divisor is the number outside the "box".
The divisor is divided into the dividend. When drawing the division house, the divisor is on the outside. The dividend is on the inside of the house, and the quotient is the answer (on top).
Multiply the quotient (answer) by the divisor (the number outside the box) and your answer should be the dividend (the number inside the box).
It is the dividend
The dividend is the number that is inside the box
If you have a dividing box thingy, the divisor is on the outside and the dividend is in the inside. Or like in the expression = 7, 2 is the divisor.
It is called a divisor. The inside number is called the dividend and the answer is the quotient. The leftover number is called the quotient but you can keep dividing until you get a decimal.
The number outside the division sign is called the "dividend." It represents the quantity that is being divided. In the context of a division equation, the number inside the division sign is known as the "divisor," while the result of the division is called the "quotient."
A door is a common object that fits this description. When a door is closed, it appears as a solid barrier on the outside but allows entry to the inside. When the door is open, the inside becomes visible from the outside, blurring the distinction between the two spaces.
That is the correct spelling for inside and outside. Inside a structure is the interior and the outside is the exterior.
To divide numbers, you set up the division problem by placing the dividend inside the division bracket and the divisor outside. Perform the division by determining how many times the divisor fits into parts of the dividend, bringing down digits as necessary. To check your work, multiply the quotient by the divisor; if the product equals the original dividend, your division is correct. If not, re-examine your calculations for potential errors.