Yes. If a number ends in 2 it is divisible by 2
A number is divisible by 3 only if the sum of its digits is. 1+1+2=4, which is not divisible by 3, therefore 112 is not.
Yes.
Both composite 75 is divisible by 5 112 is divisible by 2 ... and other numbers
Yes, evenly and the quotient is 112
1, 2, 4, 7, 8, 14, 16, 28, 56, 112.
A number is divisible by 2 if it is an even number. That is, if the last digit is divisible by 2.
8√7. Since the square root of 4 is 2 you just keep dividing the number by 4 and multiplying 2 outside the radical until you get to a number not divisible by 4. (√448 = √[112*4] = 2√112) then (2√112 = 2√[28*4] = 4√28) then (4√28 = 2√[7*4] = 8√7)
If the number formed by the last three digits is divisible by 8. Alternatively, if the number is divisible by 2, the quotient is divisible by 2 and that quotient is divisible by 2.
No.
if 2 multiplied by another number equals that number it is divisible by 2
It is divisible by 2.
There can't be any such number.' 4 ' itself is divisible by 2, so any number divisible by 4 must also be divisible by 2.