Yes, they are.
Yes.
The cubic root of 10 is an irrational number, as 10 is not a perfect cube. The only rational cubic roots are those of perfect cubes. These numbers include:1, 8, 27, 64, 125, 216, 343, 512, 729, 1000, etc.
The number is approximately 199.69 (the cube root of 27^5).
No. 27 to the third power is a regular whole number.
The square root of 27 is an irrational number
Yes.
Surds are irrational numbers and 27 is a rational number but if you mean the square root of 27 then it is an irrational number and expressed as a surd it is 3 times square root of 3.
No because the square root of 729 is 27 which is a rational number.
Yes, they are.
Yes.
An example is the square root of a number. Ex: square root of 2. This is 1 example, not the main one. Any cube root or square root which doesn't give a perfect number is an irrational number. Ex; square root and cube root of 5, since their answer will be 2.24 and 1.70 which are not perfect numbers like square roots of 25 and 64 or cube roots of 27 and 216.
The cubic root of 10 is an irrational number, as 10 is not a perfect cube. The only rational cubic roots are those of perfect cubes. These numbers include:1, 8, 27, 64, 125, 216, 343, 512, 729, 1000, etc.
The number is approximately 199.69 (the cube root of 27^5).
No. 27 to the third power is a regular whole number.
No, it is rational.
sqrt(27)