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Q: Is the square root are rational numbers?

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No. Lots of square roots are not rational. Only the square roots of perfect square numbers are rational. So for example, the square root of 2 is not rational and the square root of 4 is rational.

Only if the square root of the numerator and the square root of the denominator are both rational numbers.

Yes. The square root of 81 is 9 - a natural number and all natural numbers are rational numbers.

They are NOT rational numbers, so the question is misguided.

No, and I can prove it: -- The product of two rational numbers is always a rational number. -- If the two numbers happen to be the same number, then it's the square root of their product. -- Remember ... the product of two rational numbers is always a rational number. -- So the square of a rational number is always a rational number. -- So the square root of an irrational number can't be a rational number (because its square would be rational etc.).

The square root of 61.93 is irrational. Since rational numbers are infinitely dense there cannot be a closest rational.

Because numbers such as pi, e and the square root of 2 are not rational.

Every integer is a rational number, and some integers are perfect squares. These are the only rational numbers to have an integral square root.

There are no rational numbers between sqrt(-26) and sqrt(-15). The interval comprises purely imaginary numbers.

Rational numbers:1, 2, 3, 4, 5, 6, 7, 8, 9, 10Irrational numbers:square root of (2)square root of (3)square root of (5)square root of (6)square root of (7)square root of (8)square root of (10)square root of (11)square root of (12)square root of (13)

square root of 9 = 3 but 2, 17 and 23 are irrational numbers

No. The only square roots of integers that are rational numbers only when the integer is a perfect square.

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