The square root of 8 is an irrational number because it cannot be represented as a fraction of two integers.
It is an irrational number
It is a rational number because the square root of 64 is 8 which is a rational number
Sometimes it is and sometimes it isn't. The square root of 2 and the square root of 3 are both irrational, as is their product, the square root of 6. The square root of 2 and the square root of 8 are both irrational, but their product, the square root of 16, is rational (in fact, it equals 4).
Which 'root' are you asking to find. Square Root, Cube Root , Fourth Root, Fifth Root etc., ? Please clarify!!!!!
NO!!!! sqrt(8) = sqrt(2x2x2) = sqrt(2) X sqrt(2) x sqrt(2) = sqrt(2) x [sqrt(2)]^(2) = 2sqrt(2) = 2 X 1.414213562.... NB The square root of '2' is NOT rational . So any products of an irrational number product an irrational number. NNB The square roots of prime numbers are Irrational.
The square root of 8 is irrational and real.
irrational
It is an irrational number
No it's 8, which is not irrational.
The square root of 8 over 25 is irrational, and real.
It can't be expressed as a whole number. The square root of two is irrational, and the product of an irrational number and a rational number is also irrational. So 8*sqrt(2) is irrational.
Which 'root' are you asking to find. Square Root, Cube Root , Fourth Root, Fifth Root etc., ? Please clarify!!!!!
Yes.
Yes the result would be an irrational number.
It is a rational number because the square root of 64 is 8 which is a rational number
The square root of 128 is 8 times the square root of 2 because it's an irrational number. An estimate is 11.313708498984760390413509793678
Multiplying 8 by any irrational number will produce an irrational number. For example, if you multiply 8 by the square root of 2 (approximately 1.414), the result, 8√2, is irrational. In general, the product of a rational number (like 8) and an irrational number is always irrational.