NO!!!!
sqrt(8) = sqrt(2x2x2) = sqrt(2) X sqrt(2) x sqrt(2) = sqrt(2) x [sqrt(2)]^(2) = 2sqrt(2) =
2 X 1.414213562....
NB The square root of '2' is NOT rational . So any products of an irrational number product an irrational number.
NNB The square roots of prime numbers are Irrational.
Rational. It is a perfect square with answer exactly 8The square root of 64 is the integer 8 (8 x 8 = 64) so it is rational.
yes, square root 64 =8 which is integer, rational and real
Rational numbers:1, 2, 3, 4, 5, 6, 7, 8, 9, 10Irrational numbers:square root of (2)square root of (3)square root of (5)square root of (6)square root of (7)square root of (8)square root of (10)square root of (11)square root of (12)square root of (13)
Definitely RATIONAL. sqrt(2.56) = 1.6 NB Irrational numbers are those were the decimals recur to infinity and there is no regular order in the decimal digits. 1.6 is a terminating decimal and does NOT recur to infinity, then it is NOT irrational.
It is an irrational number
Definitely RATIONAL. sqrt(2.56) = 1.6 NB Irrational numbers are those were the decimals recur to infinity and there is no regular order in the decimal digits. 1.6 is a terminating decimal and does NOT recur to infinity, then it is NOT irrational.
Rational. It is a perfect square with answer exactly 8The square root of 64 is the integer 8 (8 x 8 = 64) so it is rational.
The square root of 64 is 8 which is a rational number
no! the square root of 8 is not retional but the cube root is retional
no! the square root of 8 is not retional but the cube root is retional
No, they are not.
It is a rational number because the square root of 64 is 8 which is a rational number
No, they are not.
yes, square root 64 =8 which is integer, rational and real
8
irrational
Which 'root' are you asking to find. Square Root, Cube Root , Fourth Root, Fifth Root etc., ? Please clarify!!!!!