No. The square root of two is an irrational number. If you multiply the square root of two by the square root of two, you get two which is a rational number.
Not always as for instance the square root of 16 is 4 which is a rational number but the square root of 2 is an irrational number.
The square root of a composite number is not always an irrational number. e.g. 4 is a composite number and its square root is 41/2 = 2, which is rational number.
No. The square root of an integer is always either an integer or an irrational number.
The square root of any positive integer can only be a WHOLE NUMBER or IRRATIONAL, so the square root of 7 is irrational.On the other hand, the sum of a rational and an irrational number is always irrational.
The square root of 2 is irrational, yet the product of it with itself is 2. So the answer is no.
It is a irrational number. Because the square root of every imperfect square is irrational number.
An irrational number is a number that never ends. An example of an irrational square root would be the square root of 11.
The square root of 2 times the square root of 2 is rational.
The square root of 27 is an irrational number
Yes. For example, the square root of 3 (an irrational number) times the square root of 2(an irrational number) gets you the square root of 6(an irrational number)
the square root of 26 is a irrational number