Square root of 25 = 251/2 = 5, which is an integer. So the square root of 25 is integer.
No, it is not.The square root of any positive integer is eitheran integer orirrational
Well, the square root of 25 is five, and 5 is an integer, yes.
square root(-5) = 2.23606798 i
no.No. The square root of 5 is an irrational number. The two closest numbers with integer square roots are 4 (with a square root of 2) and 9 (with a square root of 3). Since there are no integers between 2 and 3 and 5 lies between 4 and 9, it's pretty evident that it can't have an integer square root.
A negative square root is an imaginary number.
Yes. The square root of a natural number (positive integer) is either an integer, or an irrational number.
The square root of (-5)2 is 5. (-5 is also a square root, but "the" square root refers to the positive root in this case.) The square root of -52 is the square root of -25, or 5i. "i" is the imaginary unit. Read about "imaginary numbers" or "complex numbers" for more information. This would create confusions. Would that mean that the square of any negative number is negative?
Because the Square Root of negative 1 = i (The imaginary square root of negative 1.) and where if the square root of one number and of another number are multiplied together, the answer is equal to the square root of the two numbers combined. (Square root of 8 times the square root of 5 equals the square root of 40.) So... √(-20) =√20×√(-1) =√4×√5×i =2i(√5) The answer is 2i times the square root of 5. square root (-20) = square root (-1) x square root (20) square root (-20) = i x 4.47213595 square root (-20) = 4.47213595 i
There is no answer - 5 * -5 is 25 as a negative times a negative is a positive and - - 5 * 5 is - 25 but you cannot do this inversely if you put square root - 25 it says undefined
In increasing order, they arenegative 31 over 6negative square root 26negative 5negative 5 over 6
- (400^.5) = -(20) = -20 you just do the square root of the number, and attach the negative in front. and if you ever include the negative inside the square root, you'd have to deal with i, which is an imaginary number that signifies the square root of negative 1.
The square root of 25 is 5, which is a whole number, an integer, a natural number and a rational number.
Yes, e.g. sqrt(25)=5
It depends on whether you take the positive square root of 4 (YES) or the negative square root of 4 (No).
if there is no integer answer, they are irrationalex. sq root 5 is irrational but sq root 9 = 3 so it is rational,integer, counting numberif you are taking sq root of a negative they are imaginary ex. sqroot (-9)=========================The square roots of all positive real numbers are real numbers.The square roots of all negative real numbers are imaginary numbers.Some square roots are rational, but the vast majority are irrational.
-√25 = -5
The square root of 25 has two solutions: SQRT(25) = + 5 and -5The square root of a number, by definition, should be positive. Hence, the square root of 25 is 5. The other square root is -5. However, strictly speaking, -5 is not the square root of 25, since it is not a positive number.* * * * *The exclusion of the negative square root is plain nonsense.
sqrt(-5) + sqrt(-20) = sqrt(-5) + sqrt(4)*sqrt(-5)= sqrt(-5) + 2*sqrt(-5) = 3*sqrt(-5)3*sqrt(5)*i or 6.7082*iwhere i is the imaginary square root of -1.
A number will have both a positive and negative square root 5 x 5 = 25 and -5 x -5 = 25.
It is. (-5) is a perfectly good square root of 25.Every number has two square roots. The two square roots of 25 are [ +5 ] and [ -5 ].
No, divisors are integers and square root are often not. So the square root of 4, for example, is 2 and yes 2 is a divisor of 4. But the square root of 5 is not a divisor of 5 because it is not an integer. So sometimes square root are divisors and more often they are not.
All negative integers, when multiplied by a positive integer, or vice versa, will result in a negative integer. I. E. 5*-5=-25