no.
No. The square root of 5 is an irrational number. The two closest numbers with integer square roots are 4 (with a square root of 2) and 9 (with a square root of 3). Since there are no integers between 2 and 3 and 5 lies between 4 and 9, it's pretty evident that it can't have an integer square root.
Square root of 25 = 251/2 = 5, which is an integer. So the square root of 25 is integer.
No, it is not.The square root of any positive integer is eitheran integer orirrational
The square root of an integer is a CYCLOTOMIC integer.
no, the square root of an integer will not always be another integer. take the integer 27, for example. the square root of 27 is about 5.1961, which is not an integer.No eg square root of 17 is 4.1231056...
None. 1000 does not have an integer square root. 312 = 961 and 322 = 1024 and there is no integer between 31 and 32 so there can be no integer whose square is 1000.
Square root of 25 = 251/2 = 5, which is an integer. So the square root of 25 is integer.
Well, the square root of 25 is five, and 5 is an integer, yes.
No, it is not.The square root of any positive integer is eitheran integer orirrational
No, it is not even a real number. The square root of negative 5 is the square root of 5, times i.
The square root of an integer is a CYCLOTOMIC integer.
maybe
Negative 64 is the square root of an integer. The square root of -64 is not an integer.
Yes. The square root of a natural number (positive integer) is either an integer, or an irrational number.
no, the square root of an integer will not always be another integer. take the integer 27, for example. the square root of 27 is about 5.1961, which is not an integer.No eg square root of 17 is 4.1231056...
The square root of 3 is not an integer.
Is the square root of a 100 is a integer
No, the square root of 7 is NOT an Integer ...The square root of 7 = 2.64575131106