No.
A googol is one followed by 100 zeros ( 100 digits). That is less than a billion digits, for sure. But a googolplex is one follwed by a googol number of zeros. That is more than a billion digits, for sure.
The least whole number with 6 digits is greater because it has more digits than 5 digits.
A number with more than one digits: that is, an integer greater than 9.
The larger number is the number with more digits in this case.
It's not.4.11 is less than 4.2, even though it has more digits than 4.2 has.
It's the number that has more digits to the left of the decimal point (if there is no decimal point, it's the number with more digits). If the number of digits to the left of the decimal point is the same, find the position farthest to the left where the digits are different. The number with the greater of those two digits is the greater number. For example, 10000 is greater than 9999 because 10000 has more digits, and 6350 is greater than 6349 because the farthest-left position that is different is the tens place, and 5 is greater than 4.
90 is one such number.
So... the number has to be between 55 & 60 - and the sum of its digits must total 13... The only number that satisfies both rules is 58 !
24: the number of digits is always one more than the exponent of 10 if the exponent is positive.
No as 100000000 has more digits than 2500000 Remember; The highest value number has the highest amount of digits
No. .0123445553432 is far less than 100.
what is the number that has three digits less than 140 has7 factor the sum of the digits of the number is less than 9