i=F*sum(zi*Ci) where, i is the current density, F is Faradya's constant, zi is the velence of species i, Ci is the concentration
faradays second law
how do you use ohms law express conductance in terms of current and voltage?
The total resistance of a circuit is the sum of the supply's internal resistance and its load resistance, because they are in series with each other. This is true regardless of the magnitude of, or the variation in, the current.
The thicker the conductor, the less the current that will flow through.
One relationship is that both can flow in vacuum.
q=cv so current changes with change in voltage keeping c constant
Ohm's Law: voltage = current * resistance. If resistance is a constant, then voltage is directly proportional to current.
faradays second law
inversly proportional
how do you use ohms law express conductance in terms of current and voltage?
The total resistance of a circuit is the sum of the supply's internal resistance and its load resistance, because they are in series with each other. This is true regardless of the magnitude of, or the variation in, the current.
The thicker the conductor, the less the current that will flow through.
ohm
There is no such equation. The main reason is that there is no relationship between current and frequency.
mass=molar mass * faradays used/faradays needed 1faraday=1C/96500 Na+(aq) + e- -> Na(s) : one electron is transferred so faradays needed to produce 23.0g Na is 1 1.4kg*1000= 1400g 1400g= 23.0g/mol * Fu/1f Fu (faradays used)= Coulombs/96500(faraday constant) Fu=60.9f=Q/96500 Q=96500*60.9= 5.88*10^6 Q=I*t 5.88*106= I*3600s(1h=60min=3600s) I=1630amps
u all suck
One relationship is that both can flow in vacuum.