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I don't think so...as far as I am aware, that is impossible.
well, it's true that this comparing apples and Oranges because one is a length (perimeter) and the other is an area, but..... If you assume that he unit of area is derived from the unit of length (like m^2 and m, or in^2 and in), and you just look at the values, you can qrite this problem as:

If L is the length of one side of the square: L^2 = 4*L

and that yields L=0 (not very useful) and L=4

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15y ago

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