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Is three over eight irrational

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Anonymous

12y ago
Updated: 8/20/2019

No.

The root word in "ir-RATIO-nal" is ratio. So an irrational number is one that cannot be written as a RATIO of two integers. Your number is a ratio of the two integers 3 and 8. Thus it is RATIO-nal.

The examples of irrational number are infinity and certain square roots.

Irrational number therefore cannot be expressed as a ratio a/b, where a and b are integers and b is non-zero.

Informally, this means that an irrational number cannot be represented as a simple fraction. Irrational Numbers are those real numbers that cannot be represented as terminating or repeating decimals. As a consequence of Cantor's proof that the real numbers are uncountable (and the rationals countable) it follows that almost all real numbers are irrational.

Perhaps the best-known irrational numbers are: the ratio of a circle's circumference to its diameter π, Euler's number e, the golden ratio φ, and the square root of two √2.

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Wiki User

12y ago

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