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What are the factors of 3x3 plus 5x2-6x-10?
(3x + 5)(x2 - 2)
Factor this 9x2 plus 27?
9x(x2+3x-10) * * * * * 9x3 + 27x2 - 90x = 9x(x2 + 3x - 10) = 9x(x + 5)(x - 2).
How to factor x2-3x 9 over 4?
Multiply by 4. 4x2 - 12x + 9 factors to (2x - 3)(2x - 3) or (2x - 3)2
How do you factor -x5-x3 plus 6x?
-x(x2 - 2)(x2 + 3)
What is the least common multiple for x2-9 and 3x-9?
x**2-9-9 factors into 3,-33+-3=0x**2-9=(x-3)(x+3)3x-9=3(x-3)(x-3)=LCM
What are the factors of 3x3 plus 5x2-6x-10?
(3x + 5)(x2 - 2)
What is a common monomial factor?
(x + 1) and (x + 2) are monomial factors of the polynomial x2 + 3x + 2 (x + 1) and (x + 3) are monomial factors of the polynomial x2 + 4x + 3 (x + 1) is a common monomial factor of the polynomials x2 + 3x + 2 and x2 + 4x + 3
Factor this 9x2 plus 27?
9x(x2+3x-10) * * * * * 9x3 + 27x2 - 90x = 9x(x2 + 3x - 10) = 9x(x + 5)(x - 2).
How do you factorise- x2-3x 2 equals?
assuming x*2-3x+2:factors of -3:-1,3 --> sum: 21,-3 --> sum: -2(x-1)(x+3)
What is 2x squared add 3x?
5
How do you factor xsquared-3x-18?
We have, f(x) = x2-3x-18 f(x) = x2-3x-18 = x2-6x+3x-18 = x(x-6)+3(x-6) = (x+3)(x-6) Factors are (x-6) and (x+3).
Is it True or False that the factors for x2 plus 3x plus 4 are x plus 2 and x plus 3?
Multiply out the factors and then you can check: (x + 2)(x + 3) = x² + 3x + 2x + 6 = x² + 5x + 6 ≠ x² + 3x + 4 Therefore False.
How do you factor x3 plus x2-3x-3?
x3 + x2 - 3x - 3 x(x2 + x - 3) - 3
X2 over 3x2 -5x-2 -2x over 3 x plus 1 x 1 over x-2?
x2/(3x2 - 5x - 2) - [2x/ (3x + 1)][1/(x - 2)] = x2/(3x2 - 6x + x - 2) - 2x/(3x + 1)(x - 2) = x2/[3x(x - 2) + (x - 2)] - 2x/(3x + 1)(x - 2) = x2/(3x + 1)(x - 2) - 2x/(3x + 1)(x - 2) = (x2 - 2x)/(3x + 1)(x - 2) = x(x - 2)/(3x + 1)(x - 2) = x/(3x + 1)
Factor by grouping 3-3x plus x2-x3?
3 - 3x + x2 - x3 = (1 - x)(x2 + 3)
What is the answer for x2 plus 3x-18 equals 0?
X2 + 3X - 18 = 0What two factors of - 18 add up to 3 ??(X - 3)(X + 6)============so, by the zero sum rule,X = 3X = - 6
What is 3x-3 multiplied by x over 6 multiplied by x2-x?
(3x - 3)(x/6)(x2 - x)= (3)(x - 1)(x/6)(x)(x - 1) = (1/2)(x2)(x -1)2 = (1/2)(x2)(x2 - 2x + 1) = (1/2)x4 - x3 + (1/2)x2
