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x2/(3x2 - 5x - 2) - [2x/ (3x + 1)][1/(x - 2)]

= x2/(3x2 - 6x + x - 2) - 2x/(3x + 1)(x - 2)

= x2/[3x(x - 2) + (x - 2)] - 2x/(3x + 1)(x - 2)

= x2/(3x + 1)(x - 2) - 2x/(3x + 1)(x - 2)

= (x2 - 2x)/(3x + 1)(x - 2)

= x(x - 2)/(3x + 1)(x - 2)

= x/(3x + 1)

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Q: X2 over 3x2 -5x-2 -2x over 3 x plus 1 x 1 over x-2?
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