Yes
(x + 8)(x + 1)
(x + 8)(x + 1)
It is a polynomial of the fourth degree in X.
(x+1)(x+9)
x3-x2+5x-1 with remainder 7, which the final answer would be written as:x3-x2+5x-1+[7/(4x+3)]
(x-1)(x-4)
(x+1)(x+9)
(x + 1)(x + 2)
It is: (x+1)(x+6) when factored
X2 - X - 2(X + 1)(X - 2)===============(X + 1) is a factor of the above polynomial.
That expression can not be factored.