Both - a polynomial expression, if you like.
Yes
(x + 8)(x + 1)
(x + 8)(x + 1)
(x+1)(x+9)
It is a polynomial of the fourth degree in X.
x3-x2+5x-1 with remainder 7, which the final answer would be written as:x3-x2+5x-1+[7/(4x+3)]
(x-1)(x-4)
(x+1)(x+9)
(x + 1)(x + 2)
It is: (x+1)(x+6) when factored
X2 - X - 2(X + 1)(X - 2)===============(X + 1) is a factor of the above polynomial.
The expression ( x^3 + x^2 + x + 1 ) can be factored using polynomial identities. It can be rewritten as ( (x^2 + 1)(x + 1) ). Alternatively, it can also be expressed as ( \frac{x^4 - 1}{x - 1} ) for ( x \neq 1 ). This shows that the polynomial has roots at the complex fourth roots of unity, excluding 1.