If you mean x/5 = (1/5)x then yes (the x is in line with the fraction bar).
If you mean x/5 = 1/(5x) then no (because the x is in the denominator on the right side and in the numerator on the left side).
1 divided by 2/5 is solvable because it is the same as 1 times 5/2. 1/(2/5) = 1 x (5/2) = 5/2 = 2 1/2
5
5 x 1 = 5 and 5 divided by 60 = 0.08333 recurring
1.00000000075
2 over 3 divided by 3 over 5 [2/3] / [3/5] is the same as 2 times 5 over 3 times 3 [2*5] / [3*3] 10/9 1 1/9 1.111... The answer is 1 and 1/9
7
1 divided by 2/5 is solvable because it is the same as 1 times 5/2. 1/(2/5) = 1 x (5/2) = 5/2 = 2 1/2
1 - (3/4) = 1/4. (1/4) divided by (5/12) = 3/5. (1/4) divided by (5/12) is the same thing as (1/4) times (12/5)
The idea is to divide 1/8 divided by 1/5. This is the same as 1/8 times 5/1.
5/16X = 1 1 divided by 5/16 same as 1 * 16/5 X = 16/5 ======
1.00000000075
5
5 x 1 = 5 and 5 divided by 60 = 0.08333 recurring
40
1.00000000075
2 over 3 divided by 3 over 5 [2/3] / [3/5] is the same as 2 times 5 over 3 times 3 [2*5] / [3*3] 10/9 1 1/9 1.111... The answer is 1 and 1/9
multiply by the reciprocal if you had 1/3 divided by 5/7 you would do 1/3 times 7/5