Q: Jack has 4 more nickels than dimes and the total value of the money is 1.25 How many nickels does he have?

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There are no dimes in nickels. But 25 dimes have the same monetary value as 50 nickels have.

There are no dimes in nickels, but 20 dimes have the same purchasing value as 40 nickels have.

he has 27 dimes. to add on, he has 8 nickels to make your total of 3.10

ms lynch has 21 coins in nickels and dimes. their total value is 1.65. how many of each coin does she have

11 dimes.

4 quarters = $1.00 4 dimes = $0.40 4 nickels = $0.20 4 pennies = $0.04 Total: $1.64

Nickels are worth five cents and dimes are worth ten.

Helen has twice as many dimes as nickels and five more quarters than nickels the value of her coins is 4.75 how many dimes does she have?

All coins such as quarters, nickels, dimes, and half dollars

11 dimes and 5 nickels.

Total = 10.85 dollars.

Two nickels equal the value of one dime, therefore fourteen (14) nickels would equal the value of seven (7) dimes.

7

Tjats a pretty simple question. Anthony has. 2 pennies, 4 dimes, and 4 nickels

Letx = number of nickels 7x = number of dimes 7x (.10) + x (.05) = 3.75 .7x + .05x = 3.75 .75x = 3.75 x = 3.75/.75 = 5 nickels 7x = 35 dimes

Nickels, dimes are only slightly smaller in height than nickels.

Ten it each group.

You could (a) use trial and error; (b) write two equations; or (c) call the number of nickels "n", and the number of dimes "10-n" (since there are 10 coins in total). I will use the latter approach.Number of nickels: nNumber of dimes: 10-nFor the main equation, multiply the number of coins by the value of each coin:value of nickels + value of dimes = 805n + 10(10-n) = 80Now solve the equation:5n + 100 - 10n = 80-5n = -205n = 20n = 4So, you have 4 nickels, and 6 dimes.You could (a) use trial and error; (b) write two equations; or (c) call the number of nickels "n", and the number of dimes "10-n" (since there are 10 coins in total). I will use the latter approach.Number of nickels: nNumber of dimes: 10-nFor the main equation, multiply the number of coins by the value of each coin:value of nickels + value of dimes = 805n + 10(10-n) = 80Now solve the equation:5n + 100 - 10n = 80-5n = -205n = 20n = 4So, you have 4 nickels, and 6 dimes.You could (a) use trial and error; (b) write two equations; or (c) call the number of nickels "n", and the number of dimes "10-n" (since there are 10 coins in total). I will use the latter approach.Number of nickels: nNumber of dimes: 10-nFor the main equation, multiply the number of coins by the value of each coin:value of nickels + value of dimes = 805n + 10(10-n) = 80Now solve the equation:5n + 100 - 10n = 80-5n = -205n = 20n = 4So, you have 4 nickels, and 6 dimes.You could (a) use trial and error; (b) write two equations; or (c) call the number of nickels "n", and the number of dimes "10-n" (since there are 10 coins in total). I will use the latter approach.Number of nickels: nNumber of dimes: 10-nFor the main equation, multiply the number of coins by the value of each coin:value of nickels + value of dimes = 805n + 10(10-n) = 80Now solve the equation:5n + 100 - 10n = 80-5n = -205n = 20n = 4So, you have 4 nickels, and 6 dimes.

there r 40 nikels

56 pennies, 11 nickels, 16 dimes, 5 quarters = $3.96

You only need to solve for the number of either nickels or dimes. You can subtract that number from 86 to find the other. Since dimes are worth more, let's solve for dimes; we'll use the variable "d". First, make a chart of what we know:# dimes = "d"; 0.10 each; total cents in dimes = 10d# nickels = 86 - d, 0.05 each; total cents in nickels = 5(86-d)Total number/value of coins: total number is 86; total value $6.90, or 690 centsNow set up the equation:10d + 5(86-d) = 69010d + (5 . 86) + (5 . - d) = 69010d + 430 - 5d = 6905d + 430 = 6905d + 430 - 430 = 690 - 4305d = 260(1/5)5d = 260 (1/5)d = 52If there are 52 dimes, there must be 34 nickels (86 - 52 = 34).Let's check our work:52 dimes = $5.2034 nickels = $1.70$5.20 + 1.70 = $6.90

If n is the number of nickels and d the number of dimes, then the equations are:n + d = 160 (total number of coins) 5n + 10d = 1050 (total value). And I have thought through to the answer.

40 Dimes and 8 Nickles

245 dimes = $24.50

We have 3 times as many nickles as dimes. Let X equal our number of dimes then 3X equals our number of nickles. Now multiply these values by the value of the coins they represent. So we get : 10(X) + 5(3X)=150 cents or $1.50 next : 10X + 15X = 150 25X = 150 Divide both sides of the equation by 25 X = 6 so we have six dimes = 60 cents we have 3(X) nickels or 3(6) nickels or 18 nickels and 18 times 5 cents = 90 cents 60 cents in dimes plus 90 cents in nickels = $1.50