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John is 36, Jane is 27

When he was 27, she was 18.

The algebraic solution to the equation:

Let A = John and B = Jane, and time t = A - B (difference in ages)

If t years ago, John was twice as old

A = 2 (B - t) and substitute A - B for t

A = 2B - 2A + 2B

3A = 4B

A = 4/3 B

and since A + B = 63

4/3 B + B = 63

7/3 B = 63

B = 21 and A = 28

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Q: John is twice as old as Jane was when he was as old as she is now the sum of their ages is 63 How old are John and Jane?
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