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# John is twice as old as Jane was when he was as old as she is now the sum of their ages is 63 How old are John and Jane?

Updated: 9/18/2023

Wiki User

10y ago

John is 36, Jane is 27

When he was 27, she was 18.

The algebraic solution to the equation:

Let A = John and B = Jane, and time t = A - B (difference in ages)

If t years ago, John was twice as old

A = 2 (B - t) and substitute A - B for t

A = 2B - 2A + 2B

3A = 4B

A = 4/3 B

and since A + B = 63

4/3 B + B = 63

7/3 B = 63

B = 21 and A = 28

Wiki User

10y ago

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Q: John is twice as old as Jane was when he was as old as she is now the sum of their ages is 63 How old are John and Jane?
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