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John is twice as old as Jane was when he was as old as she is now the sum of their ages is 63 How old are John and Jane?
Wiki User
∙ 10y ago
John is 36, Jane is 27
When he was 27, she was 18.
The algebraic solution to the equation:
Let A = John and B = Jane, and time t = A - B (difference in ages)
If t years ago, John was twice as old
A = 2 (B - t) and substitute A - B for t
A = 2B - 2A + 2B
3A = 4B
A = 4/3 B
and since A + B = 63
4/3 B + B = 63
7/3 B = 63
B = 21 and A = 28
Wiki User
∙ 10y ago
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