He is 67.
beth is 5 years old.
Mary is now 22 yrs old, her brother is 11, and her father is 44 yrs old. In 22 years, her brother will be 33 and her father will be 66, while Mary will be 44 yrs old. To figure it out we need to set up algebraic equations relating everyone's current age: M (mary's age now) = 2*B (brother's age now) M = 1/2*F(father's age now) In 22 years from now, her brothers age will be half her father's age. So, B+22 = 1/2(F+22) We can use these equations to solve for everyone's age now. (1) Since Mary's age now is twice her brothers and half of her fathers we combine the first two equations to get: 2B = 1/2F or F=4B, so her father's age now is 4 times her brother's age now. (2) Using this equation and substitute the value for F in the equation which relates her brother's and father's ages 22 years from now and solve for her brother's age now. B + 22 = 1/2 (4B + 22) B + 22 = 2B + 11 B = 11, and F = 4*(11) = 44, and M=2*11=22
Sarah is 76, Margaret is 38, Jenny is 19. S + M + J = 133 S + 1/2S + 1/4 S = 133 7/4 S = 133 S = 76
Chris is 18 years old.This is algebra and the convoluted references to the ages may be confusing. However, there is one simple equation that is obviously true. If we let n be the difference in the ages of Pat and Chris, then Chris is (24-n) and his age (n) years ago was (24-n)-n and Pat is twice as old as that now.24 = 2 [(24-n)-n]24 = 2 [ 24 - 2n ]24 = 48 - 4n-24 = -4n6 = nSo Pat is now 24 and Chris is (24-n) = 18
It is 50 years.
son is 10, father is 33
6 years ago, they were 26 and 52.Now they're 32 and 58.
a father is 30 years older than his son.in 12 years,the men will be three times as old as his son.find their present ages.
There is not enough information to find the father, nor his age.The sum of their ages, in y years' time will be 7b + 2y years.
The father is 40 and his son is 14, a difference of 26 years and their combined ages equal 54.
The ages are 8 and 4
Answer: 30 (Dad) & 6 (Son) 2 years later they will be 32 & 8 which equals 40.
beth is 5 years old.
7
10
The boy is 9 years old and his sis is 18 years old
108 years Father = 72 Son = 36 (1/2 of father's) 72 + 36 = 108