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How calculate the double integral?

First we have to evaluate the inner integral using ILATE method and then evaluate the outer integral


How do you evaluate definite integrals?

In order to evaluate a definite integral first find the indefinite integral. Then subtract the integral evaluated at the bottom number (usually the left endpoint) from the integral evaluated at the top number (usually the right endpoint). For example, if I wanted the integral of x from 1 to 2 (written with 1 on the bottom and 2 on the top) I would first evaluate the integral: the integral of x is (x^2)/2 Then I would subtract the integral evaluated at 1 from the integral evaluated at 2: (2^2)/2-(1^2)/2 = 2-1/2 =3/2.


Von-karman momentum integral equations for boundary layers?

yes


What is the difference between triple integral and volume integral?

While I searching for the answer to this question, I totally confused. Atlast I reach in one thing that we may compute some volume integrals by using double integral but to evaluate a triple integral we should go through all the three integrals.


How can the boundary term be integrated by parts in the context of the given problem?

In the context of the problem, the boundary term can be integrated by parts by applying the formula for integration by parts, which involves breaking down the integral of the product of two functions into a combination of the derivatives of one function and the integral of the other function. This allows for simplification and evaluation of the boundary term in the given problem.


What has the author A A Bakr written?

A. A. Bakr has written: 'The boundary integral equation method in axisymmetric stress analysis problems' -- subject(s): Boundary element methods, Strains and stresses


Which of the following is a characteristic of thiamine nutrition?

It is an integral part of the nerve cell membrane


How does integral differ from a normal integral?

There are two types of integrals: definite and indefinite. Indefinite integrals describe a family of functions that differ by the addition of a constant. Definite integrals do away with the constant and evaluate the function from a lower bound to an upper bound.


What are the similarities between integral and peripheral?

integrai Essential or necessary for completeness; constituent ... and peripheral is Related to, located in, or constituting an outer boundary or periphery.


When parked on the flightline which of the following vehicles are required to be chocked?

vehicles without an integral braking system


Evaluate the integral x4 dx from 4 to 2?

x^(4) dx = x^(5) /5 [2,4] => 4^(5)/5 - 2^(5)/5 => 2^(10) / 5 - 2^(5) / 5 [2^(10) - 2^(5) ] / 5 = [1024 - 32] / 5 = 992/5 = 198.4


How do you evaluate the integral of 2udu divided by 1 plus u squared?

for the integral of (2x)dx/(1+x2 ) Take (1+x2 ) as your 'u' substitution. find du, du= 2x dx use u substitution to write new integral, integral of du/u the integral of du/u= ln abs(u) + C therefore, your original problem becomes an answer with ln ln abs (1+x2) + C *abs refers to absolute value of the parentheses