logically no because if it is a yes, then the light reaching the detector is greater than the light which was produced by the machine in the first place. But you may get transmittance greater than 100 because some parameters of your experiment may not be right.
None of the physical materials in the world are perfectly transparent. Even when light passes through air, some part of it gets scattered due to dust particles on its way. however, when one is interested in knowing the transparency of a material ( solid/liquid), such losses can be held constant and the photometer can be calibrated to estimate the trasmittance(transparency) by selecting the endpoints. for example, if a piece of thick black India rubber is held between a source of light and the detector, one can set the output to read zero transmittance and after removing it to 100 % transmittance. If any material is now held between the two, the output will show a change in transmittance that truly responds to only the sample and no other interfering inputs. With absorbance, this may not be true since in certain cases, the loss attributed to absorbance might in fact be due to other mechanisms such as scaterring or (regular)reflection.
i think sodium but im not 100 percent sure
triton x-100 stock percent? 100% ?
yes
Original answer: Because it gives off more power. Updated answer: In general, because the 100-watt bulb produces more total light (lumens) because it also consumes more power than the 60-watt bulb. However, a 60-watt can produce more lumens than a 100-watt bulb, depending on the types of bulbs in question.
Absorbance = -log (percent transmittance/100)
47 percent out of 100 percent is 47 percent (0.47 x 100 percent = 47 percent). More clearly, 47 % / 100 % = 47 / 100 = 0.47
22%= 100% - 78%= 22%
14% more
Yes, it can.
100% alcohol is more effective because of the more alcohol concentration in the drink.
Glass, 100 percent pure water, and light.
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None of the physical materials in the world are perfectly transparent. Even when light passes through air, some part of it gets scattered due to dust particles on its way. however, when one is interested in knowing the transparency of a material ( solid/liquid), such losses can be held constant and the photometer can be calibrated to estimate the trasmittance(transparency) by selecting the endpoints. for example, if a piece of thick black India rubber is held between a source of light and the detector, one can set the output to read zero transmittance and after removing it to 100 % transmittance. If any material is now held between the two, the output will show a change in transmittance that truly responds to only the sample and no other interfering inputs. With absorbance, this may not be true since in certain cases, the loss attributed to absorbance might in fact be due to other mechanisms such as scaterring or (regular)reflection.
No, an amount cannot be decreased by more than 100 percent. To decrease by more than 100 percent would mean that the amount is actually going into the negative values, which is not possible in most contexts. A decrease of 100 percent means that the amount is reduced to zero.
a percent yield will be above 100 if the product used are wet or more likely impure.
Yes. Fifty percent would be half of 100, and eighty-three percent is greater than fifty percent.