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No it is not. The log of any number, with the same number as the base, is always 1.
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∙ 9y ago
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Log3 81 x log2 8 x log4 2 equals x?
log3 81 × log2 8 × log4 2 = log3 (33) × log2 (23) × log4 (40.5) = 3 × (log3 3) × 3 × (log2 2) × 0.5 × (log4 4) = 3 × 1 × 3 × 1 × 0.5 × 1 = 9 × 0.5 = 4.5
What is log3 9root3?
log3 [ 9 sqrt(3) ]= log3 [ 9 ] + log3 [ sqrt(3) ]= log3 [ 32 ] + log3 [ 31/2 ]= 2 + 1/2= 2.5
What does x equal in log 3 x equals 4?
log3(x)=4 x=3^4 x=81
What is Log3 3 plus log3 x plus 2 equals 3?
log33+log3x +2=3 log33+log3x=1 log3(3x)=1 3x=3 x=1 Other interpretation: log33+log3(x+2)=3 log3(3(x+2))=3 3(x+2)=27 x+2=9 x=7
How do you solve Log base 3 of 7x equals Log base 3 of 2x plus Log base 3 of 0.5?
There is not a solution. Knowing how logarithms work helps. On the right hand side you have: log3(2*x) + log3(0.5).Adding logs is equivalent to multiplying (inside the log). This becomes: log3(0.5 * 2*x) = log3(x).Subtract log3(x) from both sides: log3(7x) - log3(x) = 0.Subtracting logs is equivalent to division (inside the log): log3(7x/x) = 0.So log3(7) = 0, which is Not true. No Solution.
How do you solve log base 3 of 7-log base3 of x equals 4?
log37 - log3x = 4 log3(7/x) = 4 7/x = 34 = 81 x = 7/81
How do you solve this log x base 3 plus log x3 base 9 equal 0?
log3(x) + log9(x^3)=0 for any t >0 logt(x) = ln(x)/ln(t) so log9(x) = ln(x) / ln (9) = ln (x) / ( 2 * ln 3) = log3(x) /2 or log3(x) = 2 log9(x) log9(x^n) = n * log9(x) So log3(x) + log9(x^3) = log3(x) + 6 log3(x) = 7 log3(x) 7 log3(x) = 0 => log3(x) = 0 => x = 1
How do you solve log1 plus log2 plus log3?
log1 + log2 + log3 = log(1*2*3) = log6
What is 13 in base 3?
If you mean: log3(13) then it is 2.334717519
What is x plus x plus 2 x equal 3?
log33+log3x +2=3 log33+log3x=1 log3(3x)=1 3x=3 x=1 Other interpretation: log33+log3(x+2)=3 log3(3(x+2))=3 3(x+2)=27 x+2=9 x=7
Is the following correct log3 divided by log2 equals 5 divided by 3 and if yes what are the steps?
To check the statement . . .(log3)/(log2)=5/3 ( ? )Get rid of the denominators:5log2=3log3Logarithmic property:log2^5=log3^3Eliminate the logarithms:2^5=3^3Simplify:32=27This is incorrect (that's your answer)==================================Answer #2:The answer to the question is: "No, that is incorrect"
How do you evaluate the expresssion log3 sqrt243?
log(3√243)=log(27√3)
