log3 81 × log2 8 × log4 2 =
log3 (33) × log2 (23) × log4 (40.5) =
3 × (log3 3) × 3 × (log2 2) × 0.5 × (log4 4) = 3 × 1 × 3 × 1 × 0.5 × 1 = 9 × 0.5 = 4.5
x: x2 - 81 = 0
x2 = 81 Square root both sides:- x = +/- 9
Oh, dude, that's like some math stuff right there. So, if you're looking for a number that you can multiply by itself three times to get 81, you're basically asking for the cube root of 81. And guess what? The cube root of 81 is 3! So, yeah, 3 multiplied by itself three times equals 81. Math can be cool sometimes, I guess.
The number is three.
It is: (81*9*64)+19 = 46,675
log3(x)=4 x=3^4 x=81
log37 - log3x = 4 log3(7/x) = 4 7/x = 34 = 81 x = 7/81
No it is not. The log of any number, with the same number as the base, is always 1.
81% = 81/100
81 x 81 = 6561
How about: 9 times 9 = 81 or 81 times 1 = 81
81 * 22 = 1,782
100x2-81
729/81 = 9
3 to the power of 4 = 81
It is: 9^2 = 81
81 times 7 or 7 times 81 equals 567