You add up all the numbers except one of the fives and then take that total and subtract it by the five you didn't use
9 x 3 - 5 - 1 = 21
(21 - (4 x 5))3
9+9+9+9=36-5-5-5-5=16+3+3+3-3=22+1-1-1/1=21
3*5=15+3+3=21
The factors of 15 are: 1, 3, 5, and 15.The prime factors of 15 are: 3 and 5.The factors of 21 are: 1, 3, 7, and 21.The prime factors of 21 are: 3 and 7.
Example: 1 + 3/5 = ? Step 1: make the denominators the same: 1 = 5/5 Step 2: put the 5/5 into the problem in place of the 1: 1 + 3/5 = 5/5 +3/5 Step 3: add the numerators: 5/5 + 3/5 = 8/5 Example 2: 3 + 6/7 = ? 3 = (3x7)/7 = 21/7 21/7 + 6/7 = 27/7
1 over 21. 5/7 - 2/3 = 15/21 - 14/21 = 1/21
28/1 ÷ 21/5 = 20/3 or 62/3
5/14 * 21/35 = 5/14 * 3/5 = 1/14 * 3/1 = 3/14
9 + 5 + 3 + 3 + 1 + 1 = 21
2/3 + 5/7 (the common denominator is 21, the LCM of 3 and 7) = 2*7/3*7 + 5*3/7*3 = 14/21 + 15/21 = (14 + 15)/21 = 29/21 = (21 + 8)/21 = 21/21 + 8/21 = 1 + 8/21 = 1 8/21
Factors of 21: 1, 3, 7, 21 Factors of 30: 1, 2, 3, 5, 6, 10, 15, 30