Need motor voltage, amperage and phase to give you an anwer.
fuse size for 5 horse power compressor?
In North America the smallest size breaker found in a home distribution panel is rated at 15 amps
Assuming being fed by c32 breaker for start load minimum cable size SWA is 70mm which will go to 456 meters
Minimum size is 10 gauge with a 30 amp breaker. To be safe I would install an 8 gauge with a 40 amp breaker.
Use only AWG # 10 copper.
The formula you are looking for is I = W/E.
500 amp breaker with 250 mcm cu conductors, NEC list this motor as drawing 192 amps X 250% = 480amps go to the next standard size of breaker which would be a 500.
A breaker is based on the amount of current that the motor draws. This amperage should be taken off of the motors nameplate. In motors of a specific horsepower the amperage is proportional to the voltage the motor uses. Without the motors voltage this question can not be answered.
It depends on what the amperage of the motor is. The motors amperage depends on the voltage of the motor. The higher the voltage the motor operates on the lower the amperage. So unless the amperage from the motor's nameplate is stated an answer can not be given.Just remember that the feeder capacity to the motor has to be 125% of the motors full load amperage and the breaker protecting the conductors to the motor has to be rated at 250% of the motors FLA. This higher breaker size allows the motor to start without tripping a normal size breaker that is rated for the lower conductor size.
LRA (locked rotor amps) is not used to calculate the breaker size. Breaker's are used to protect the size of the conductor that is connected to it. Motor calculations are based on the motor's FLA (full load amps).Conductor size is 125% of the motor's FLA.Breaker size is 250% of the motor's FLA.This is the only occasion when the breaker is sized larger that the conductors maximum amperage rating. This is due to the motor drawing up to 300 to 600% of its FLA when starting.If you state the motor's wattage, voltage or amperage this calculation can be calculated here.
In North America the smallest size breaker found in a home distribution panel is rated at 15 amps
Assuming being fed by c32 breaker for start load minimum cable size SWA is 70mm which will go to 456 meters
50 amps
One horsepower (electric motor) is 746 watts, so ten horsepower is 7460 watts. Divide that by a power factor (assumed) of 0.8 and you get 9325 volt-amps. Divide that by a voltage (again, assumed) of 240 and you get 39 amperes. For calculation purposes the electrical code book states that a 10 horsepower motor at 240 volts will draw 50 amps. The motor's nameplate amperage that is driving the rotary phase converter should all ways be used first. The electrical code requires a breaker for a motor to be 250% of the motor's operating full load current. 250% of 39 amperes is 97 amperes. I would use a 100 ampere breaker for a 10 horsepower motor. If the motor rating is used from the code book values, then 50 x 250% would equal 125 amps and that is the size of the breaker that must be used. This is the reason that the motor's exact name plate amperage rating should be used. In the long run feeder wire costs could make a saving in the overall projected costs.
50 amps
30 amp breaker with #10 gauge copper wire
Minimum size is 10 gauge with a 30 amp breaker. To be safe I would install an 8 gauge with a 40 amp breaker.
It depends, it has to do with the weight, horsepower, and size of motor. The heavier the car is the slower. The less horsepower the car is slower. and if the motor is small the slower it goes.