Q: Ms Lynch has 21 coins in nickels and dimes Their total value is 1.65 How many of each coin does she have?

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Ten dimes, fifteen nickels

he has 27 dimes. to add on, he has 8 nickels to make your total of 3.10

110 nickels and 40 dimes my little brother had the same problem

11 dimes.

16 % of the coins are dimes. 4 of a total of 25.

The coins in the store's cash register total $12.50. The cash register contains only nickels, dimes, and quarters. There are twice as many dimes as nickels. There are also twice as many quarters as dimes. How many quarters are in the cash register?

Eighteen

10 Nickels 2 Quarters = $1.00 4 Dimes 7 Nickels 1 Quarter = $1.00 8 Dimes 4 Nickels = $1.00

Tjats a pretty simple question. Anthony has. 2 pennies, 4 dimes, and 4 nickels

7 dimes, 3 nickels and 15 pennies. You're welcome.

117 nickles

There are several combinations of 14 US coins which total 1 Dollar. Among them are: - 6 Dimes and 8 Nickels. - 1 Quarter, 6 Dimes, 2 Nickels and 5 Pennies. - 2 Quarters, 2 Dimes, 5 Nickels and 5 Pennies.

7

14 pennies = 0.09 13 nickels = 0.65 3 dimes = 0.30 total 30 coins = 1.09

Three of the 6 coins had to be nickels. The six coins are 1 quarter, 1 dime, 3 nickels, and 1 penny.

The coins in a cash register amount to $12.50. One coin combination that would produce this total is 40 quarters, 19 dimes, 2 nickels, and 50 pennies. Another combination is 20 quarters, 50 dimes, 45 nickels, and 25 pennies.

Two quarters Three nickels Three pennies

If n is the number of nickels and d the number of dimes, then the equations are:n + d = 160 (total number of coins) 5n + 10d = 1050 (total value). And I have thought through to the answer.

Since the smallest of these currency values (the nickel) is equal to 5 cents, the number of five cent coins that go into a dollar is equal to 20. It is impossible to have a combination of 35 nickels and dimes whose sum is exactly equal to a dollar.

117 Alternative method: If all the coins were dimes he would have $41.90; He is $5.85 short of that figure Every 5c short represents 1 nickel replacing a dime 585/5 = 117 nickels (and 302 dimes).

30 coins 6 dimes = 60c 4 nickels = 20c 20 pennies = 20c Total $1

20 dimes = 2.00 20 nickels = 1.00 Total = 3.00

There are 83 coins. If there are N nickels then there are (83 - N) dimes. Davida has nickels worth 5N and dimes worth 10(83 - N) but. 5N + 10(83 - N) = 695 5N + 830 - 10N = 695 5N = 830 -695 = 135 therefore N = 135/5 = 27 : D = 83 - N = 83 - 27 = 56 Davida has 27 nickels and 56 dimes.

there r 40 nikels

You need to define variables for the different types of coins, write the corresponding equations, then solve them. One equation for each fact. Here are the equations:5N + 10D + 25Q = 1250 D = 2N Q = 2D