Ten dimes, fifteen nickels
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Oh, dude, let's break it down. So, if we let x be the number of dimes, then the number of nickels would be x + 70. Since there are 150 coins total, we can set up the equation x + (x + 70) = 150. Solving it, we find that there are 60 dimes and 130 nickels. Easy peasy, lemon squeezy!
You need to define variables for the different types of coins, write the corresponding equations, then solve them. One equation for each fact. Here are the equations:5N + 10D + 25Q = 1250 D = 2N Q = 2D
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If Keoki has 14 quarters and 8 dimes (for a total of 22 coins), she has $3.50 and $0.80 or $4.30 in coins. If Keoki has 15 quarters and 7 dimes (for a total of 22 coins), she has $3.75 and $0.70 or $4.45 in coins. If Keoki has 22 coins that are all dimes and quarters and their value in total is $4.35 as asked, there isn't a combination of coins that will permit her to have both 22 coins and $4.35 worth of coins.
Let x be the number of nickles. So, the number of dimes is 40 - x. So, 0.05x + 0.10(40 - x) = 3.50 0.05x + 4 - 0.10x = 3.50 - 0.05x + 4 = 3.50 subtract 4 to both sides; -0.05x = - 0.50 divide by - 0.05 to both sides; x = 10 Thus, Jack has 10 nickles and 30 dimes.