There is one significant digit in 0.05 (the 5... the zero before it is a placeholder) and two significant digits in 3.1. So your answer should have one sig fig: 0.05 x 3.1 = 0.155 = 0.2 (with correct # of sig figs)
25.488000000000003
The rules for identifying significant figures when writing or interpreting numbers are as follows: All non-zero digits are considered significant. For example, 91 has two significant figures (9 and 1), while 123.45 has five significant figures (1, 2, 3, 4 and 5). Zeros appearing anywhere between two non-zero digits are significant. Example: 101.1203 has seven significant figures: 1, 0, 1, 1, 2, 0 and 3. Leading zeros are not significant. For example, 0.00052 has two significant figures: 5 and 2. Trailing zeros in a number containing a decimal point are significant. For example, 12.2300 has six significant figures: 1, 2, 2, 3, 0 and 0. The number 0.000122300 still has only six significant figures (the zeros before the 1 are not significant). In addition, 120.00 has five significant figures since it has three trailing zeros.
2 significant figures.
The number 3400 has two significant figures. The rules for significant figures can be found by using the link to our friends at Wikipedia.
The rule when rounding off numbers is "If the first figure to be discarded is 5 or more then the previous figure is increased by 1". When 16490 is rounded off to 2 significant figures then the first figure to be discarded is 4. As this is less than 5 then the previous figure (6) is not increased by 1. 16490 to 2 significant figures is 16000.
25.488000000000003
It isn't clear what the question is. If you are supposed to multiply or divide, and if by "signification figures" you mean significant digits, do the multiplication (or division), then round to three significant digits - since the least-precise of the numbers only has three significant digits.
Significant figures are calculated using various rules.ÊAll non-zero numbers are significant and all zeros that are to the right of the decimal point as well as at the end of a number are significant.ÊTherefore, 1.050L has 4 significant figures.
145.992 using only four significant figures is 146.0
61.37795276 in four significant figures is 61.38
21,600 using only four significant figures is still 21,600.
840 using four significant figures is 840.0
There are 3 significant figures
You multiply each ingredient by 300. There is no need for scientific notation.
The rules for identifying significant figures when writing or interpreting numbers are as follows: All non-zero digits are considered significant. For example, 91 has two significant figures (9 and 1), while 123.45 has five significant figures (1, 2, 3, 4 and 5). Zeros appearing anywhere between two non-zero digits are significant. Example: 101.1203 has seven significant figures: 1, 0, 1, 1, 2, 0 and 3. Leading zeros are not significant. For example, 0.00052 has two significant figures: 5 and 2. Trailing zeros in a number containing a decimal point are significant. For example, 12.2300 has six significant figures: 1, 2, 2, 3, 0 and 0. The number 0.000122300 still has only six significant figures (the zeros before the 1 are not significant). In addition, 120.00 has five significant figures since it has three trailing zeros.
2 significant figures.
Answer: four. All written decimals are significant (even if it is 0).However if you have a physics computation where one number turns out to be x = 2.0 (2 significant figures) and the other turns out to be y = 37.15 (4 significant figures), then to compute the product x*y you should take the least of these significant numbers you are using. Hence, you will find thatx*y = 2.0 * 37.15 (= 74.30) = 74 (rounded to the nearest number with 2 significant digits only.)So, it depends on the context you are using this number in.